As shown in figure, a homogeneous 50-kg rigid block is suspended by the three springs whose lower ends were originally at the same level. Each steel spring has 24 turns of 10-mm-diameter on a mean diameter of 100 mm, and G = 83 GPa. The bronze spring has 48 turns of 20-mm-diameter wire on a mean diameter of 150 mm, and G=42 GPa. Compute the maximum shearing stress in each spring using approximate equation.

As shown in figure, a homogeneous 50-kg rigid block is suspended by the three springs whose lower ends were originally at the same level. Each steel spring has 24 turns of 10-mm-diameter on a mean diameter of 100 mm, and G = 83 GPa. The bronze spring has 48 turns of 20-mm-diameter wire on a mean diameter of 150 mm, and G=42 GPa. Compute the maximum shearing stress in each spring using approximate equation.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.

Question

As shown in figure, a homogeneous 50-kg rigid block is suspended by the three
springs whose lower ends were originally at the same level. Each steel spring has
24 turns of 10-mm-diameter on a mean diameter of 100 mm, and G = 83 GPa.
The bronze spring has 48 turns of 20-mm-diameter wire on a mean diameter of
150 mm, and G=42 GPa. Compute the maximum shearing stress in each spring
using approximate equation.
Steel
ww
1 m
Steel
50 kg
2m
Phosphor
Bronze

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