As an illustration of the difficulties that may arise in using the method of undetermined coefficients, consider X' = Form the complementary solution to the homogeneous equation. help (formulas) help (matrices) x.(t) = c1 + c2 Show that seeking a particular solution of the form x.(t) = e2"ā, where a = is a constant vector, does not work. In fact, if x, had this form, we would arrive at the following contradiction: az = help (numbers) and az = - Ip. help (numbers) Show that seeking a particular solution of the form xp(t) = te' a, where a = is a constant vector, does not work either. In fact, if x, had this form, we would arrive at the following contradiction: az = help (numbers) and aj = help (numbers) and az = help (numbers)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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As an illustration of the difficulties that may arise in using the method of undetermined coefficients, consider
x +
Form the complementary solution to the homogeneous equation.
help (formulas)
help (matrices)
x.(t) = c1
C2
:
Show that seeking a particular solution of the form x,(t) = e2 ā, where a =
is a constant vector, does not work. In fact, if x, had this form, we would arrive at the following
contradiction:
aɔ =
help (numbers)
and
a, =
help (numbers)
Show that seeking a particular solution of the form xp(t) = te2" ā, where a =
is a constant vector, does not work either. In fact, if x, had this form, we would arrive at the following
a2
contradiction:
a1
help (numbers)
and
aj =
help (numbers)
and
help (numbers)
Transcribed Image Text:As an illustration of the difficulties that may arise in using the method of undetermined coefficients, consider x + Form the complementary solution to the homogeneous equation. help (formulas) help (matrices) x.(t) = c1 C2 : Show that seeking a particular solution of the form x,(t) = e2 ā, where a = is a constant vector, does not work. In fact, if x, had this form, we would arrive at the following contradiction: aɔ = help (numbers) and a, = help (numbers) Show that seeking a particular solution of the form xp(t) = te2" ā, where a = is a constant vector, does not work either. In fact, if x, had this form, we would arrive at the following a2 contradiction: a1 help (numbers) and aj = help (numbers) and help (numbers)
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