As an electron moves through a region of space, its speed decreases from 9.60 × 106 m/s to 2.10 × 106 m/s. The electric force is the only force acting on the electron.       Across what potential difference did the electron travel?

A particle has a charge of +1.76 μC and moves from point A to point B, a distance of 0.201 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +8.87E-4 J. Calculate the magnitude of the electric force that acts on the particle.

Two positive point charges are 4.50 cm apart. If the electric potential energy is 71.0 μJ , what is the magnitude of the force between the two charges?

A proton is initially at rest at a point where the potential is 473 V. Some time later the proton is at a point where the potential is 191 V. If no force other than the electrostatic force acts on the proton, what is its final kinetic energy?

Oppositely charged parallel plates are separated by 5.09 mm. A potential difference of 600 v exists between the plates. (a) What is the magnitude of the electric field between the plates? V N/C (b) What is the magnitude of the force on an electron between the plates? N (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.36 mm from the positive plate? Apply the definition of work in terms of force and displacement. J

A particle with a charge of -1.0 μC and a mass of 3.0 x 10-6 kg is released from rest at point A and accelerates toward point B, arriving there with a speed of 11 m/s. The only force acting on the particle is the electric force. What is the potential difference VB - VA between A and B? If VB is greater than VÃ, then give the answer as a positive number. If VÅ is less than VÃ, then give the answer as a negative number. Number i Units >

Inside a particular radiation therapy device, there is a uniform electric field with a magnitude 385 N/C pointing in the positive x-direction. An electron, initially at rest, moves a distance of 3.60 cm in this field. (a) How much work (in J) does the electric field do on the electron? J (b) What is the change in potential energy (in J) of the entire system (radiation therapy device plus electron)? J (c) What is the velocity (in m/s) of the electron after it moves the 3.60 cm distance? m/s magnitude direction ---Select--- ✓

A particle has a charge of +1.20 μC and moves from point A to point B, a distance of 0.240 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA-EPEB= +9.40 x 10-4 J. (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the electric field that the particle experiences. (a) Number i (b) Number i Units Units

A particle with a charge of +4.20 nC is in a uniform elec tric field Ē directed to the left. It is released from rest and moves to the left: after it has moved 6.00 cm, its kinetic energy is found to be +1.50 x 10 6 J. (a) What work was done by the electric force? (b) What is the potential of the starting point with respect to the end point? (c) What is the magnitude of Ē?

Two tiny metal spheres A and B of masses mA = m and mB = have equal positive charges q. The spheres are connected by a massless nonconducting string of length d, which is much greater than the radii of the spheres. NOTE: Express your answers in terms of m, q, d, and eg. (a) What is the electric potential energy of the system? U = (b) Suppose you cut the string. At that instant, what is the acceleration of sphere A? AA = (c) Suppose you cut the string. At that instant, what is the acceleration of sphere B? Ав (d) A long time after you cut the string, what is the speed of sphere A? VA = (e) A long time after you cut the string, what is the speed of sphere B? UB =