Aromatics Chloroalkanes Estersi 1.06 0.95 1.58 1.12 0.29 0.43 0.06 0.79 0.65 1.45 0.91 0.06 0.51 0.09 0.10 0.17 0.82 1.15 0.57 0.83 0.44 0.89 1.12 1.16 0.43 0.55 0.53 0.17 1.05 0.61 0.34 0.60 Is there a significant difference in the mean sorption rate for the three solvents at 0.05 level of significance ? What is the mean square within ? Round-off answer to 4 decimal places
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- 19 1.328 1,/29 2.093 2.539 2.86T 19 20 1.325 1.725 2,086 2.528 2.845 20 21 1.323 1.721 2.080 2.518 2.831 21 22 1.321 1.717 2.074 2.508 2.819 22 23 1.319 1.714 2,069 2.500 2.807 23 24 1.318 1.711 2.064 2.492 2.797 24 25 1.316 1.708 2.060 2.485 2.787 25 26 1.315 1.706 2.056 2.479 2,779 26 27 1.314 1.703 2.052 2.473 2.771 27 28 1.313 1.701 2.048 2.467 2.763 28 29 1.311 1.699 2.045 2.462 2.756 29 30 1.310 1.697 2.042 2.457 2.750 30 31 1.309 1.696 2.040 2.453 2.744 31 32 1.309 1.694 2.037 2.449 2.738 32 33 1.308 1.692 2.035 2.445 2.733 33 34 1.307 1.691 2.032 2.441 2.728 34 35 1.306 1.690 2.030 2.438 2.724 35 36 1.306 1.688 2.028 2.434 2.719 36 37 1.305 1.687 2.026 2.431 2.715 37 38 1.304 1.686 2.024 2.429 2.712 38 39 1.304 1.685 2.023 2.426 2.708 39 40 1.303 1.684 2.021 2.423 2.704 40 45 1.301 1.679 2.014 2.412 2.690 45 50 1.299 1.676 2.009 2.403 2.678 50 60 1.296 1.671 2.000 2,390 2.660 60 70 1.294 1.667 1.994 2.381 2.648 70 80 1.292 1.664 1.990 2.374 2.639 80 90 1.291 1.662 1,987 2.368…24. The following data resulted from a stress-strain experiment where a given strain was applied and stress measured. Negative values of stress indicate compression. Deformation D Stress S (MPa) -2 -8.5 -1 -1.2 0.2 10.5 We want to apply linear regression to find the value of a and b in the equation S-aD + bD The problem will involve the assembly of an overdetremined linear system of the type Ar-b where x is the unknown vector with the values of a and b. Which of the following is the correct A matrix?1.542 1.585 1.532 1.466 1.499 1.611 1.598 1.498 1.6 1.504 1.545 1.558 1.622 1.466 1.546 1.494 1.548 1.626 1.555 1.712 1.442 1.443 1.699 1.701 1.44 1.608 1.52 1.478 1.542 1.511 1.698 1.88 1.11 1.21 1.987 1.39 1.459 1.533 1.532 1.523 1.397 1.487 Find a 99% CI on the mean tar content. Find the upper and lower limits.(Do not round off the values until you get the final answer)
- Thank you STAT 115 Mini Project-5 Constructing a Confidence Interval Constructing a Confidence Interval with M&M's Are the colors evenly distributed in a bag of M&M's? Is the company reporting accurate color percentages for their product? This activity will guide you through constructing a confidence interval for the proportion of M&M's in a particular color. You have long suspected that the colors are not evenly distributed in a bag of M&M's. Out of curiosity, you decide to construct a confidence interval for the proportion of orange M&M's in a bag of peanut M&M's. Open the dataset 'MMs_Data.csv file in StatCrunch. 1. Treat the dataset as your bag of peanut M&M's (a simple random sample). Count the number of orange M&M's and the total number of M&M's in your bag. Then determine the proportion of your M&M's that are orange. Number of orange M&M's: 13 Total number of M&M's: 65 Proportion of orange M&M's: 0.2 2. Verify that the requirements for constructing a confidence interval for the…S-adenosyl methionine (SAM-e) is a naturally occurring compound in human cells that is thought to have an effect on depression symptoms. Suppose that a researcher is interested in testing SAM-e on patients who are struggling with Alzheimer's. She obtains a sample of n% = 30 patients and asks each person to take the suggested dosage each day for 4 weeks. At the end of the 4-week period, each individual takes the Beck Depression Inventory (BDI), which is a 21-item, multiple-choice self-report inventory for measuring the severity of depression. The scores from the sample produced a mean of M = 26.2 with a standard deviation of s = 2.97. In the general population of Alzheimer's patients, the standardized test is known to have a population mean of p= 28.1. Because there are no previous studies using SAM-e with this population, the researcher doesn't know how it will affect these patients; therefore, she uses a two-tailed single-sample t test to test the hypothesis. From the following,…Complete the following using compound future value. (Use the Table provided.) (Round your answers to the nearest cent.) Time 11 years Principal $ 15,200 Rate Compounded 2 % Annually Amount Interest
- What is the confidence level of each of the following confidence intervals for u? Complete parts a through e. Click the icon to view the table of normal curve areas. a. x+1.96 % (Round to two decimal places as needed.) b. x+1.645 % (Round to two decimal places as needed.) c. X+2.575 % (Round to two decimal places as needed.) d. x+1.282 % (Round to two decimal places as needed.) e. x+0.99 % (Round to two decimal places as needed.)Commercial Residential4.17 9.795.38 5.973.22 8.095.42 5.814.91 8.552.59 3.973.53 8.113.01 8.664.69 10.356.17 6.980.33 5.675.13 4.056.35 6.156.47 9.853.98 5.670.2 0.3 0.3 0.3 0.3 0.3 0.3 0.4 0.4 0.4 0.5 0.5 0.5 0.5 0.5 0.6 0.6 0.7 0.8 1.0 1.1 1.1 1.2 1.2 1.6 1.6 2.1 2.1 2.3 2.4 2.5 2.7 2.7 2.7 3.2 3.4 3.6 3.8 4.0 4.0 5.0 5.6 8.2 9.6 10.6 13.0 14.1 15.1 15.2 30.4 Use the given data to construct a boxplot and identify the 5-number summary.
- Household Paper Plastic1 3.27 0.632 2.41 1.133 11.42 12.814 7.98 6.095 6.33. 3.866 12.32 11.177 6.96 7.608 16.39 9.709 6.83 3.5710 5.86 3.9111 9.41 3.3612 6.44 8.4013 14.33. 6.4314 2.80 5.9215 16.08 14.3616 6.05 2.7317 13.61 8.9518 12.73. 14.8319 9.55 9.2020 6.16 5.8821 6.67 6.0922 7.72 3.8623 15.09 9.1124 8.82 11.8925 11.08 12.4726 13.05 12.3127 9.83 6.2628 7.57 5.9229…4.764.724.744.554.914.744.784.714.804.784.784.754.794.824.914.834.684.744.704.804.704.764.704.834.934.744.844.824.764.774.724.784.834.754.744.684.844.714.714.764.664.784.734.744.924.774.804.794.864.644.784.704.754.784.764.834.664.774.834.784.694.814.684.784.884.724.854.854.814.744.804.824.844.704.854.704.814.724.794.63 What is the mean, median, and mode? (you may want to use your calculator or the average and median functions in Excel!) What could be some reasons for variation in the weights of the Kisses®? Note: Take time answering this one. There are lots of things to consider here and I'll be looking for a well thought out answer with several given reasons contributing to the variation. Of course, the wrappers and tags could vary but what about the drops of chocolate themselves? Why aren't they all the same? Would you say that there are any two Kisses that have exactly the same weight? (I mean exactly the same weight!) Explain why or why not. How many Kisses® were there in the…Date DJIA S&P 500 Day 1 35405.24 4536.54 Day 2 35629.33 4579.38 Day 3 35111.16 4467.44 Day 4 35089.74 4510.53 Day 5 35091.13 4493.87 Day 6 35462.78 4511.54 Day 7 35768.06 4577.18 Day 8 35241.59 4514.08 Day 9 34738.06 4408.64 Day 10 34566.17 4411.67 Day 11 34988.84 4461.07 Day 12 34934.27 4485.01 Day 13 34312.03 4390.26 Day 14 34079.18 4358.87 Day 15 33596.61 4314.76 Day 16 33131.76 4235.50 Day 17 33223.83 4278.70 Day 18 34058.75 4394.65 Day 19 33892.60 4363.94 Day 20 33294.95 4316.26 Day 21 33891.35 4396.54 Day 22 33794.66 4353.49 Day 23 33614.80 4318.87 Day 24 32817.38 4211.09 Day 25 32632.64 4180.70 Day 26 33286.25 4287.88 Day 27 33174.07 4249.52 Day 28 32944.19 4194.31 Day 29 32945.24 4183.11 Day 30 33544.34 4252.45 Day 31 34063.10 4367.86 Day 32 34480.76 4421.67 Day 33 34754.93 4473.12 Day 34 34552.99 4471.18 Day 35 34807.46 4521.61 Day 36 34358.50 4466.24 Day 37 34707.94 4510.16 Day 38 34861.24 4553.06…