Area = (-3, 3)- УА x = y2 - 4y x = 2y — y²

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Please answer the questions with steps and correct answer.

**Find the Area of the Shaded Region Below**

The image shows a graph with two curves plotted on a coordinate plane. The region enclosed by these curves is shaded in yellow.

### Graph Details:

- **Curves:**
  - The red curve is described by the equation \( x = y^2 - 4y \).
  - The blue curve is described by the equation \( x = 2y - y^2 \).

- **Axes:**
  - The horizontal axis is labeled \( x \).
  - The vertical axis is labeled \( y \).

- **Intersection Point:**
  - The curves intersect at the point \((-3, 3)\).

- **Shaded Region:**
  - The enclosed area between the two curves is shaded in yellow, forming an almond-like shape.

**Objective:**
Calculate the area of the shaded region.

**Formula to use:**
To find the area between two curves \( x = f(y) \) and \( x = g(y) \) from \( y = c \) to \( y = d \), use the integral:

\[
\text{Area} = \int_c^d [f(y) - g(y)] \, dy
\]

**Input Box:**
- Area = [Input box provided for the answer]
Transcribed Image Text:**Find the Area of the Shaded Region Below** The image shows a graph with two curves plotted on a coordinate plane. The region enclosed by these curves is shaded in yellow. ### Graph Details: - **Curves:** - The red curve is described by the equation \( x = y^2 - 4y \). - The blue curve is described by the equation \( x = 2y - y^2 \). - **Axes:** - The horizontal axis is labeled \( x \). - The vertical axis is labeled \( y \). - **Intersection Point:** - The curves intersect at the point \((-3, 3)\). - **Shaded Region:** - The enclosed area between the two curves is shaded in yellow, forming an almond-like shape. **Objective:** Calculate the area of the shaded region. **Formula to use:** To find the area between two curves \( x = f(y) \) and \( x = g(y) \) from \( y = c \) to \( y = d \), use the integral: \[ \text{Area} = \int_c^d [f(y) - g(y)] \, dy \] **Input Box:** - Area = [Input box provided for the answer]
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