Apply the alternating series test to discuss convergence or divergence of the given series. Σ(−1)n+1 ¹ nº n=1

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
icon
Related questions
Question

Can someone help me thanks

Apply the alternating series test to discuss convergence or divergence of the given series.
Ο
α
Σ(-1)"+1
n=1
O
O
O
h=.
Since
M8
Σ
(-1)
n=1|
Since
Since
1
n=1 n4
α
Σ (-1)
n =]
(-1)'
) "+1
Since
n=1 h
Σ (-1)
n=1
n+1
το
1
n=1 n'
Σ (-1)
n=1
1
n
00 1
n+1
n=1 n'
converges, then the original series is absolutely convergent.
n+1
η
1
· diverges, then the original series is divergent.
1
n²
+1
n
1
Σ which is a convergent p-series.
n=1 n'
00
Σ
n=1 ht
n-
1
2
∞0 1
Σ
n=1 n2
converges, then the original series is conditionally convergent.
Σ
n=1
which is a divergent harmonic series.
1
which is a convergent geometric series.
1
-Σ.
η
n=1 h
diverges, then the original series is divergent.
which is a divergent p-series.
which is a convergent p- series.
00
1
Since Σ converges, then the original series is conditionally convergent.
n=1 n°
Transcribed Image Text:Apply the alternating series test to discuss convergence or divergence of the given series. Ο α Σ(-1)"+1 n=1 O O O h=. Since M8 Σ (-1) n=1| Since Since 1 n=1 n4 α Σ (-1) n =] (-1)' ) "+1 Since n=1 h Σ (-1) n=1 n+1 το 1 n=1 n' Σ (-1) n=1 1 n 00 1 n+1 n=1 n' converges, then the original series is absolutely convergent. n+1 η 1 · diverges, then the original series is divergent. 1 n² +1 n 1 Σ which is a convergent p-series. n=1 n' 00 Σ n=1 ht n- 1 2 ∞0 1 Σ n=1 n2 converges, then the original series is conditionally convergent. Σ n=1 which is a divergent harmonic series. 1 which is a convergent geometric series. 1 -Σ. η n=1 h diverges, then the original series is divergent. which is a divergent p-series. which is a convergent p- series. 00 1 Since Σ converges, then the original series is conditionally convergent. n=1 n°
Expert Solution
steps

Step by step

Solved in 4 steps

Blurred answer
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Precalculus
Precalculus
Calculus
ISBN:
9780135189405
Author:
Michael Sullivan
Publisher:
PEARSON
Calculus: Early Transcendental Functions
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning