
ENGR.ECONOMIC ANALYSIS
14th Edition
ISBN: 9780190931919
Author: NEWNAN
Publisher: Oxford University Press
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Appledale Dairy is considering upgrading an old ice-cream maker. Moderate upgrading costs $7050 now and yields annual savings of $4800 in the first year, and decreases by $300 dollars every year after that. If the upgraded ice-cream maker will last for seven years, what is the present worth of the upgrading option? Use a present worth comparison. Appledale's MARR is 9 percent.
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- Ridgley Custom Metal Products (RCMP) must purchase a new tube bender. RCMP's MARR is 13 percent. The company is considering three models: Economic Life 5 years 5 years 3 years Using the annual worth method, which of the three tube benders should RCMP buy? Model T A X First Cost $120,000 $170,000 $210,000 Yearly Net Savings $50,000 $80,000 $85,000 Salvage Value $20,000 $25,000 $80,000 Click the icon to view the table of compound interest factors for discrete compounding periods when i = 13%. The annual worth of Model T is $ The annual worth of Model A is $ The annual worth of Model X is So, the Model $ is the better choice to buy. (Round to the nearest cent as needed.)arrow_forwardYour company is determing whether or not it should invest in a new pallet wrapping station. The station would cost $6,500 and your company's MARR is 13%. You estimate the purchasing a pallet wrapper would save you $2,000 in labor annually, and at the end of 3 years you would realize a salvage value of $400. How would you calculate the present worth of this investment in Excel?arrow_forwardAn alternative method of construction would be to construct a bridge of pre-stressed concrete construction. The estimated life of such a structure will be 20 years. The first cost would be $150,000 and it would have a salvage value of $20,000 at the end of its useful life. The yearly maintenance cost would be $2,000. What would be the total yearly cost? The interest rate is 8%.arrow_forward
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