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Answes given, y"-sy =1622 let's Solve it step by step 1. Homogeneaus Solution The characteristic equation Corresponding to the homogeneous part of the equation 93: 43-8=0 Solving this equation , we find the boots r = 2, −1+3√3, −1–1√ So the homogenous Solution 73: 2x Y₁(x) = Ge² + Ge* 68 (√3x) + Czetin (13x). 2. particulas Solution the particulas Solution, we'll use for the method of undetermined coefficients. Since a quadrate polynomial. We'll assume 16x2 18 the partedal Solution has = Ax +B+C. the form yp (x)

Answes given, y"-sy =1622 let's Solve it step by step 1. Homogeneaus Solution The characteristic equation Corresponding to the homogeneous part of the equation 93: 43-8=0 Solving this equation , we find the boots r = 2, −1+3√3, −1–1√ So the homogenous Solution 73: 2x Y₁(x) = Ge² + Ge* 68 (√3x) + Czetin (13x). 2. particulas Solution the particulas Solution, we'll use for the method of undetermined coefficients. Since a quadrate polynomial. We'll assume 16x2 18 the partedal Solution has = Ax +B+C. the form yp (x)

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 35E
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Answes given, y"-sy =1622 let's Solve it step by step 1. Homogeneaus Solution The characteristic equation Corresponding to the homogeneous part of the equation 93: 43-8=0 Solving this equation , we find the boots r = 2, −1+3√3, −1–1√ So the homogenous Solution 73: 2x Y₁(x) = Ge² + Ge* 68 (√3x) + Czetin (13x). 2. particulas Solution the particulas Solution, we'll use for the method of undetermined coefficients. Since a quadrate polynomial. We'll assume 16x2 18 the partedal Solution has = Ax +B+C. the form yp (x)
Transcribed Image Text:Answes given, y"-sy =1622 let's Solve it step by step 1. Homogeneaus Solution The characteristic equation Corresponding to the homogeneous part of the equation 93: 43-8=0 Solving this equation , we find the boots r = 2, −1+3√3, −1–1√ So the homogenous Solution 73: 2x Y₁(x) = Ge² + Ge* 68 (√3x) + Czetin (13x). 2. particulas Solution the particulas Solution, we'll use for the method of undetermined coefficients. Since a quadrate polynomial. We'll assume 16x2 18 the partedal Solution has = Ax +B+C. the form yp (x)
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