Answer: Target Reaction: 1/2H (g) + 1/2Cl_(g) → HC(g) 9. COCl-(g) + H20(1) → CH2Cl2(1) + O2(g) 2HCI(g) + 1/202(g) → H 2 O(1) + Cl2(g) CH2Cl2(1) + H2(g) + 3/20 2(g) – COCL2(g) + 2H 20(1) Step Reactions: AH = -47.5 kJ AH = 105 kJ AH = -402.5 kJ

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part A 1. Concentration of Known NiCl2 Stock Solution ___500________ mM   Tube Number   Blank #1 #2 #3 #4 #5 2. Volume of Known NiCl2 Stock Solution Pipetted Into Tube 0.00 mL 1.50 mL 3.00 mL 4.50 mL 6.00 mL 7.50 mL 3. Volume of Distilled Water Pipetted Into Tube 11.00 mL 9.50 mL 8.00 mL 6.50 mL 5.00 mL 3.50 mL 4. Total Volume of Solution In Tube 11.00 mL 11.00 mL 11.00 mL 11.00 mL 11.00 mL 11.00 mL 5. Diluted Concentration of NiCl2 In Tube ----------- 68.2 mn 136mn 204mn 273mn 341mn 1. Equation for the Best-Fit Straight Line Y=3822x+4.7446 2. Absorbance at λmax for Diluted Unknown 0.87 3. Concentration of NiCl2 in Diluted Unknown 25.693 mM Determine the dilution factor for your diluted unknown U1 based on how you prepared the solutions in Part A. Record this on your report sheet in Part D #4.

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