answer Adj. departure of DA only

Q: L K H 3 m A G B C E F |-2 m--2 m--2 m--2 m--2 m-|-2 m-| 20 kN 30 kN 40 kN

A: For determining forces in members of truss two methods are used which are as follows: Method of…

Q: fc' Mpa 20.1 fy Mpa 335

A: fc' = 20.1 Mpa fy = 335 Mpa

Q: FOR ALL PROBLEMS, DETERMINE THE AFD, SFD, AND BMD MAKING SURE To SHOW AL WORK REQUIRED OBTAIN EACH…

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Q: KN 4m 上 4m 100 t Kat 200

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Q: This is in the surveying subject the first 3 was answered already a b and c, kindly answer the rest…

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Q: A lot has the following latitude and departure. Line ADJUSTED DEPARTURE(m) ADJUSTED LATITUDE(m) AB…

A: As per DMD method: Area=∑(DMD×Latitude)2…

Q: 22/ Draw shear and momenk beam shown below 20 KN 2 m 3.

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Q: Discuss Corrected CPT Parameters

A: The cone penetration or cone penetrometer take a look at (CPT) may be a methodology wont to verify…

Q: A Find AA, B s' B für 3 Q Search ܣܐ 2K/₁ f Find AB, Oc Con side B-C), 8 (unside C-D). pla 4K $31…

A: To calculate support reactionsThe moment at right support = 0

Q: Convert the following W (a) 53° 55' (b) 45' 175° (c) 222° 35' (d) 305° 55'

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Q: Please perform the analysis to find the elev of BM 2.  Also find the error, indicate the order and…

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Q: The following consecutive reading were taken with a level and 4m leveling staff ground at common…

A: Common interval = 30 mElevation of point A = 220.50 mTo calc:1) Reduced levels of points given2)…

Q: Given: A : 290 kN 8: 487KN C: 197KN a ef :v 6:610 い290 Find : x anal y companent For ce A, Resultent…

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Q: Determine cleflection a=2.5 at b.) Determine cleflection at b=0.4 C) Determine the rotation at c=1 a…

A: Given:Required:Note: As per bartleby guidelines, only first 3 subparts among multiple subparts need…

Q: DPD Method Course ADJ. LAT ADJ. DEP DPD 2A АВ 69.92 -97.22 BC 57.14 82.10 CD -68.99 67.12 DA -58.07…

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Q: g- 1.305 ). Determine the corrected ievel difference between the two points C& D

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Q: A flag post was erected on the top of a building. If vertical angle subtended at bottom and top of…

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Q: omplete the table by filling the shaded parts. Show full solution a. Find LEC, REC and BSE.

A: LINE bearing(θ) bearing in radians Length (L) Lat(LCOSθ) departure(LSINθ) Correction in lat…

Q: B. Clculate the straight line of least sqoae of errors that fits the following dete 1 3. 4. 1.85…

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Q: 1) Find, the unknowns ("aaa" through "Beg") in the table of closed traverse starting from BM and…

A: Rise and fall are the value equal to the difference in reduced levels between the two consecutive…

Q: Write a short note on adjustments of line ranger

A: Short note on adjustment of line ranger:

Q: Helght of Torget Une of Slght Assume 90* Horlzontal Une Level Surface HJ. Level Surfoce G Mean Soo…

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Q: 3. If gage A reads -20 kPa, determine the elevations of points L, N, Q and 9. Z et El. 65.00 E G Air…

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Q: Gven: PROBUEM 2. ド: 500 6: 36ON Find: mc MA MB. MF mo ME F 2m

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Q: STA BM-100 0+10 0+12 0+ 16 4 0+22 TP1 0+34.2 0+34.3 +42 5 TP2 0+45 1+ 48 6 BS HI FS IFS ELEV 328.70…

A: When the height of a point is its vertical distance up or down the surface of a reference plane it…

Q: How was the sum of  angles received? How was the closure error calculated?

A: Given: 3 angles of a triangle  Required: Calculate sum of measured angle and also find closure error…

Q: After getting knocked out by Luffy, Don Chinjao decided to buy a lot and retire for good. The…

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Q: The call for adjoiner must yield when the footsteps of the original surveyor and the lines and…

A: This question is from survey engineering subject

Q: Find allowable(e ) (m) So thut lOmpa 65+ S140 MP., Gü € 50 50 KN 12 kN Y m 250 mm 3m K50 150

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Q: J.74 3.45 (FS) GATEAT BM-1 Elev 568.75m) 1.28 BS) 3.32 (FS) TP- 1.85 (BS) 479 FS) 3.92 FS) 785) TP-2…

A: to compete the differential level notes.  figure given in the question can be considered as FBD

Q: Prob.59. The following readings were observed with a dumpy level 0.795, 1.535, 2.855, 3.125, 0.945,…

A: R.L of BM = 608.4 m  Chainage point (C.P) = after 4 and 8 reading

Q: Detarnine the vertical sport B of the coupond (GERBER) becn. Assıune there sapin at C.(Aisrolle the…

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Q: THE MAGNITUDE OF THE RESULTANT O TOTAL MOMENT ACTING ON POINT "A" TOTAL MOMENT ACTING ON POINT "B“ ο…

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Q: Sef Mem CALD B C AB BC CD DA Tength Bearinte SX 425 Lsino 2815 LCD LDA 159° 30.00 14.883. 221° 6200…

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Q: d=0:02 m 7m Lelom Uzo-2% find 7

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Q: Backsight Foresight STA HI Elev Hair Rdg Mean Rdg S Hair Rdg Mean Rdg S 1.153 125.00M 0.936 BM,…

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Q: Q.I A line of level is run from B.M.1 (elevation-106.40m) to B.M. 2(clevation-110.50m). The field…

A: The field observations were recorded as given in question, Given B.M.1 (elevation=106.40m) B.M.2…

Q: FIND CENTROID (C.4.) FIND Ix WIZX40 A-1して in Ix307m W12X40 WT 6X20 A- 5.84 エ14.イm ye1.09 im. WIZX40…

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Q: 에 ho ho lo

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Q: Dist. (m) | Mean Dist. (m) Line Azimuth Bearing Latitude Departure from South 1- 2 27.35 171° 18' 2…

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Q: 2. Complete the mising dota. UNE DISTANCE (meter) BEARING 1-2 123.4450 140.2336 146.3536 164.86…

A: To find Missing data from the table. a) length of the line 1-2 b) bearing of the line 1-2.

Q: 1. Complete the table using Compass Rule Bearing S563 E Course AB BC CD DE EF FG Total: Distance…

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Q: COURSE ADJ LAT ADJ DEP АВ +380.36 +5.52 ВС +228.48 -466.46 CD -624.13 -303.15 DE -297.25 +293.76 EF…

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Open Channel Flow

Open channel flow is a branch of fluid mechanics. It deals with the flow of fluid in an open conduit or free surface. In an open channel flow, gravity induces the flow of water whose surface is open to the air. This flow is free-falling rather than confined in rigid body conduits. The open channel flow depends upon two parameters that are the cross-section of the conduit and the velocity profile. Practical examples of open channel flow are streams, rivers, canals, and other drainage systems.In open channel flow, the cross-sectional area of at least one of the sides is exposed to air, and the surface of water faces atmospheric pressure. This flow is also known as free gravity flow. The cross-sectional area of the conduit can be either man-made or a natural channel. For instance, the flow in rivers and streams are natural conduits, and the flow in a canal and sanitary systems are man-made or engineered channels.