An underwater device which is 2m long is to be moved at 4 m/sec. If a geometrically similar model 40 cm long is tested in a variable pressure wind tunnel at a speed of 60 m/sec with the following information, Parater = 998kg/m* Pair at Standard atmospheric pressure = 1.18kg/m3 1.80 x 10-5 Pa-s at local atmospheric pressure and Hwater = 1 x 10-3 Pa-s then the pressure of the air in the model used times local atmospheric pressure Hair %3D is

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8th Edition
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Chapter5: Analysis Of Convection Heat Transfer
Section: Chapter Questions
Problem 5.70P
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An underwater device which is 2m long is to be moved at 4 m/sec. If a geometrically
similar model 40 cm long is tested in a variable pressure wind tunnel at a speed of 60
m/sec with the following information,
Poir at Standard atmospheric pressure = 1.18kg/m³
Pwater = 998kg/m3
Hair = 1.80 x 10-5 Pa-s at local atmospheric pressure and
Hwater = 1 × 10-3 Pa-s then the pressure of the air in the model used
times local atmospheric pressure
is
Transcribed Image Text:An underwater device which is 2m long is to be moved at 4 m/sec. If a geometrically similar model 40 cm long is tested in a variable pressure wind tunnel at a speed of 60 m/sec with the following information, Poir at Standard atmospheric pressure = 1.18kg/m³ Pwater = 998kg/m3 Hair = 1.80 x 10-5 Pa-s at local atmospheric pressure and Hwater = 1 × 10-3 Pa-s then the pressure of the air in the model used times local atmospheric pressure is
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