An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" () which we write hth, ttt, etc.For each outcome, let N be the random variable counting the number of tails in each outcome. For example, if the outcome is htt, then N (htt) = 2. Supposethat the random variable X is defined in terms of N as follows: X=2N²-4N-4. The values of X are given in the table below.Outcome hht hth tth tht tttValue of X-6 -6-4-42Value .x of XCalculate the probabilities P(X=x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilitiesin the second row.P(X=x)0htt thh hhh-40-4-600X

The question is about probability distribution Given : To find : Prob. P ( X = x ) of the prob.…

Answered: An ordinary (fair) coin is tossed 3…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (*) which we write hth, ttt, etc. For each outcome, let N be the random variable counting the number of heads in each outcome. For example, if the outcome is ttt, then N (ttt) = 0. Suppose that the random variable X is defined in terms of N as follows: X=2N -2. The values of X are given in the table below. Outcome ttt hth tht htt thh hhh hht tth Value of X -2 2 0 0 2 4 2 0 Calculate the probabilities P(X=*) of the probability distribution of X. First, fill in the first row with the valuesof X. Then fill in the appropriate probabilities in the second row. Value x of X ___ ___ ___ ___ P(x=x) ___ ___ ___ ___
Let X,, X2, and X3 be independent random variables, each are binomially distributed with n = 100 and p = 0.2. Let A = X,– 2X2 and B = X3 + 3X1. Find PAB- %3D %3D
A red die is rolled and then a green die. Let X=2(Spots on Red) + (Spots on Green). Determine the pmf for the random variable. In particular f(6)
Two coins are taken at random (without replacement) from a bag containing 6 nickels, 5 dimes, and 4 quarters. Let X denote the random variable given by the total value of the two coins. Find E(X). (Round your answer to four decimal places.)
Suppose that X is a N(3,4) random variable and suppose that Y=5X+2. Determine P(Y>18.5).
A pathologist has been studying the frequency of bacterial colonies within the field of a microscope using samples of throat cultures from healthy adults. Long-term history indicates that there is an average of 2.80 bacteria colonies per field. Let r be a random variable that represents the number of bacteria colonies per field. Let O represent the number of observed bacteria colonies per field for throat cultures from healthy adults. A random sample of 100 healthy adults gave the following information. 2 3 4 5 or more 13 18 28 16 17 8 (a) The pathologist wants to use a Poisson distribution to represent the probability of r, the number of bacteria colonies per field. The Poisson distribution is given below. P(r) = r! Here 1 = 2.80 is the average number of bacteria colonies per field. Compute P(r) for r = 0, 1, 2, 3, 4, and 5 or more. (Round your answers to three decimal places.) P(0) = P(1) = Р(2) Р(3) 3 P(4) = %3D P(5 or more) = (b) Compute the expected number of colonies E = 100P(r)…
13) A player spins two spinners. The outcome of each spinner is 1, 2, or 3. Each outcome is equally likely. Define the random variable X to be the maximum of the two numbers on the spinners. What is E[X]? a. 2/3 b. 5/3 c. 20/9
An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let R be the random variable counting the number of heads in each outcome. For example, if the outcome is tth, then =Rtth1. Suppose that the random variable X is defined in terms of R as follows: =X−R2−3R4. The values of X are given in the table below. Outcome htt tht hth thh ttt hhh hht tth Value of X −6 −6 −6 −6 −4 −4 −6 −6 Calculate the values of the probability distribution function of X, i.e. the function p X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row.
An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let R be the random variable counting the number of heads in each outcome. For example, if the outcome is ttt, then R(ttt) = 0. Suppose that the random variable X is defined in terms of R as follows: X= 2R- 4R-4. The values of X are given in the table below. Outcome ttt tth hht thh tht hhh htthth Value of X -4 -6 -4 -4 -6 -4 Calculate the values of the probability distribution function of X, i.e. the function py. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value x of X Px (x) olo
If a random variable X is defined such that E[(X -3)21 = 18 and E(X- 1)1=34, Then the values of u and a are. =3/5 and o=6 and a
Consider a random variable x N(6, 4). Then Prob(X = 12) equals: %3D 0.0 O 0.25 O 0.5 O 0.75 O 0.32

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