An object of mass m₁ is located at a height h, above the ground (that is considered as the reference for the gravitational potential energy, PE, = 0) and has a potential energy PE 1. If the mass is doubled (m₂ = 2m₁) and the height is reduced to h₂ h₁ ,then the new potential energy PE92 will be equal to: O PEg2= PEg1 O PEg2= 2 PEg1 O PEg2= 4 PEg1 O PEg2= 0.25 PEg1 O PEg2= 0.5 PEg1

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Chapter1: Units, Trigonometry. And Vectors
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An object of mass m₁ is located at a height h₁ above the ground (that is considered
as the reference for the gravitational potential energy, PE, = 0) and has a potential
energy PE 1. If the mass is doubled (m₂ = 2m₂) and the height is reduced to h₂ =
then the new potential energy PE92 will be equal to:
h₁
PEg2= PEg1
PEg2= 2 PEg1
PEg2= 4 PEg1
O
PEg2= 0.25 PEg1
O PEg2= 0.5 PEg1
Transcribed Image Text:An object of mass m₁ is located at a height h₁ above the ground (that is considered as the reference for the gravitational potential energy, PE, = 0) and has a potential energy PE 1. If the mass is doubled (m₂ = 2m₂) and the height is reduced to h₂ = then the new potential energy PE92 will be equal to: h₁ PEg2= PEg1 PEg2= 2 PEg1 PEg2= 4 PEg1 O PEg2= 0.25 PEg1 O PEg2= 0.5 PEg1
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