College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Block 1 (10 kg) is located on the surface of a table. A rope pulls on block 1 with a horizontal tension of 58 N to the right and a vertical tension of 60N upward. The coefficient of kinetic friction between the block and the surface equals 0.2. On a sheet of paper, draw the free body diagram for block 1 using the two- subscript notation from class. After completing the free body diagram, enter below each force and its x & y-components. Remember that the x-component is the "i" component and the y-component is the "j" component. FORCES on BLOCK 1 Weight force on block 1 by Earth W1E : jN Tension force on block 1 by Rope T1R = jN %3D Normal force on block 1 by Surface N1S = i+ jN %3D Frictional force on block 1 by Surface f1S = i + jN !! Submit Answer Tries 0/2 What is the acceleration a of block 1? j m/s2 a =arrow_forwardTwo blocks each of mass m are fastened to the top of an elevator as in the figure below. The elevator has an upward acceleration a. The strings have negligible mass. (a) Find the tensions T1 and T2 in the upper and lower strings in terms of m, a, and g. T1 = T2 = (b) Compare the two tensions and determine which string would break first if a is made sufficient large.arrow_forwardA wooden box containing several objects slides down a ramp at a constant speed when the ramp is inclined at 18°. The total mass of the box and its contents is 6.3 kg. A second box of equal mass slides down a different ramp at a constant speed. The second ramp is inclined at 26°. Compare the coefficients of friction of the two ramps. Explain reasoning (I need help with which forces act in certain spaces and why)arrow_forward
- The diagram shows overhead views of four situations in which forces act on a block that slides on a frictionless ice surface. In which situations would it be possible for the block to move along the floor with a constant velocity? (Assume the magnitudes of the forces can be adjusted slightly). I do not understand this at all. I know gravitational force is downwards, and frictional force is opposing the pushing force, but how do I solve this?arrow_forwardHow do I draw the net force on the following object given the component forces in the table? Please explain step by step.arrow_forwardThe following diagrams show the magnitude and direction of several forces acting on some boxes with different masses. For each one, find the magnitude (with correct units) and direction of both the net force and acceleration.arrow_forward
- Two boxes are connected by a massless string across a massless frictionless pulley. Box S has a mass M and box H has a mass m. write Newton's 2nd law equation for these objects, horizontal component only for box S and vertical component only for box H. solve algebraically for acceleration of the boxes. given M = 8.4 kg and m = 5.7 kg, use the equation from the previous part to find the value of the acceleration. use this answer to find the tension of the string.arrow_forwardYou push a block along the ice, as shown below. Which of these could be the net force equations in the x and y directions? Use the convention that N is the normal force, f is the frictional force, Fg is the force of gravity, and Fapp is the force you apply.arrow_forwardA sled, of mass = 6.50 kg, is sliding down a snow-covered hill that has a slope of 45.0 degrees. There is an applied force pushing down on the sled perpendicular to the incline of 80.4N. The coefficient of kinetic friction between the sled and snow is 0.100. Which of the free body diagrams below is draw correctly for the situation above? Continuing the question above: A sled, of mass = 6.50 kg, is sliding down a snow-covered hill that has a slope of 45.0 degrees. There is an applied force pushing down on the sled perpendicular to the incline of 80.4N. The coefficient of kinetic friction between the sled and snow is 0.100. Determine the acceleration of the sled down the slope. Report your answer in meters per second squared, but only enter the numerical value.arrow_forward
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