An object is launched on the moon at 32 feet per second (f/s) from a 384-foot tall tower. The equation for the object's height s at time t seconds after launch is s(t)=-32t^2+32t+384, where s is in feet. When does the object strike the moon’s surface and why?

Solve -5 2 x = [²5 3] x 31 x' 8

Does the equation represent a function? −20x^2=−y−9

An object is launched at 15 meters per second from a 50-meter tall platform. The equation for the objects height h at time t seconds after the launch is h(+)=-4.9t^2+15t+50, where h is in meters. Round answers to 2 decimal places. A- how long will it take for the object to reach it's maximum height? B- what will the maximum height of the object be? C- how long will it take the object to hit the ground?

y=xlnx−x

Determine the solution for the following equation: (8x-8)^((3)/(2))=64.

Solve for x: 2sinx=3