An object is launched on the moon at 32 feet per second (f/s) from a 384-foot tall tower. The equation for the object's height s at time t seconds after launch is s(t)=-32t^2+32t+384, where s is in feet. When does the object strike the moon’s surface and why?
An object is launched on the moon at 32 feet per second (f/s) from a 384-foot tall tower. The equation for the object's height s at time t seconds after launch is s(t)=-32t^2+32t+384, where s is in feet. When does the object strike the moon’s surface and why?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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An object is launched on the moon at 32 feet per second (f/s) from a 384-foot tall tower. The equation for the object's height s at time t seconds after launch is s(t)=-32t^2+32t+384, where s is in feet. When does the object strike the moon’s surface and why?
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