An object 24.0 cm from a concave mirror creates a virtual image at -33.5 cm. What is the focal length of the mirror? (Mind your minus signs.) (Unit = cm) %3D

Question 6 of 15 A 3 cm tall object is placed in front of a concave mirror. The magnitude of the mirror's focal length is 4 cm. An image is formed on the back side of (behind) the mirror and is located a distance of 2 cm from the mirror. What is the object distance and the image height? 1.33 cm, 4.50 cm 4.00 cm, 1.50 cm 2.00 cm, 1.50 cm 1.33 cm, 1.50 cm 4.00 cm, 4.50 cm

The mirror equation relates the object distance, d0, the image distance, di, and the focal length, f, of a mirror as1 / d0 + 1 / di = 1 / fWhile in other topics, distance and length are strictly non-negative, in optics we introduce the following sign conventions: Object distance is positive for a real object and negative for a virtual object. Image distance is positive for a real image and negative for a virtual image. Focal length is positive for a converging mirror and negative for a diverging mirror (a) Select the best choice to complete this statement. A real object placed in front of a converging mirror creates a real image  under all circumstances. under no circumstances. when the object is between the focal point and the mirror. when the object is farther than the focal length from the mirror. (b) Select the best choice to complete this statement. A real object placed in front of a diverging mirror creates a virtual image  under all circumstances. under no circumstances.…

3. A concave makeup mirror is designed to produce a virtual image that is one and a half times the size of the object when the distance between the object and the mirror is 17.0 cm. What is the focal length of the mirror? cm

When a young girl looks in a 6.0-cm radius, spherical Christmas tree ornament, she sees an image of her face that is upright and four times smaller than its actual size. How close is her face to the ornament?   a. 9.0 cm   b. 7.0 cm   c. 5.0 cm   d. 8.0 cm   e. 6.0 cm

IP A magician wishes to create the illusion of a 2.66- m-tall elephant. He plans to do this by forming a virtual image of a 46.0-cm-tall model elephant with the help of a spherical mirror. You may want to review (Pages 923 - 928). If the model must be placed 2.65 m from the mirror, what radius of curvature is needed? R= -4.52 1Π ΑΣΦ 4 Submit Previous Answers Request Answer Part C * Incorrect; Try Again; 2 attempts remaining How far from the mirror will the image be formed? di 15.3 m Submit ? Previous Answers m Review ✓ Correct Here we learn how to determine the distance from the mirror to the image. The image distance is negative, thus, the image is behind the mirror.

4. An object placed 15.0 cm in front of a convex mirror produces an image that is three-fourths the size of the object. What is the focal length of the mirror?(include the proper algebraic sign to reflect the nature of the mirror) cm

2. An object is located 60.0 cm to the left of a concave mirror (with R = 30 cm). a) What is the focal length for this mirror? Include the correct sign (positive or negative). b) Use the mirror equation to find the location of the image. State whether the image is real or virtual. c) Use the magnification equation to find the magnification of the image. State whether the image upright or inverted, and magnified or diminished. d) Confirm your answer to part (b) by drawing a ray diagram on the figure to find where image is located (Use three rays). 1

d = 2 / 4 | f = -4cm 2. The figure shows a diverging mirror with a focal length of -4cm. An object is 4cm to the left of the mirror and is 2cm tall. object b. Find the magnification of the image. c. Find the height h, of the image. makada wa k ho h₂ = a. a. Fill in the blanks above, and find d, the image-to-lens distance. समयमा 67% + @ matatatata ਲਈ ਲੋਕ ਅ daripada diverging mirror SEMUA ALLERGO heen Ladk STREET PERSE ASTERSUN dime APRESEN Ename E Para 6 d. Draw the focal point(s) of this mirror on the picture above. e. Draw the image above at the correct location and with the correct size & orientation.

4. A convex (converging) lens produces a real, inverted image of an object that is magnified 2.20 times when the object is 37.0 cm from the lens. What is the focal length of the lens? cm