
Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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l need the answer in 30 mints please please please.
![An iron bar 2.0 cm x 3.0 cm x 10.0 cm at a temperature of 95 °C is dropped into a
barrel of water at 25 °C. The barrel is large enough so that the water temperature
rises negligibly as the bar cools. The rate at which heat is transferred from the bar
to the water is given by the expression Q (J/min) = UA (T, - T)
where U = 0.05 J/(min cm °C)] is a (cm) is the exposed surface area of the bar,
T, and Tw are the surface temperature of the bar and the water temperature,
respectively. The heat capacity of the bar is 0.46 J/(g °C). Heat conduction in iron
is rapid enough for the temperature T to be considered uniform throughout the bar.
a) Write an energy balance on the bar
b) Plot the expected plot of T, versus t and then curve fitting.
M = (60 cm')(7.7 g/cm') = 462 g
= 0.46 kJ/(kg.°C), T, = 25°C
%3D
C,
U = 0.050 J/(min - cm2.°C)
A = 2[(2)(3) + (2)(10) + (3)(10)]Jem?
= 112 cm2](https://content.bartleby.com/qna-images/question/27e5e864-a7e8-4624-8093-41baa89bb6d8/508f12bd-562e-4616-ae1a-ab3d0937b000/a1hwbqt_thumbnail.jpeg)
Transcribed Image Text:An iron bar 2.0 cm x 3.0 cm x 10.0 cm at a temperature of 95 °C is dropped into a
barrel of water at 25 °C. The barrel is large enough so that the water temperature
rises negligibly as the bar cools. The rate at which heat is transferred from the bar
to the water is given by the expression Q (J/min) = UA (T, - T)
where U = 0.05 J/(min cm °C)] is a (cm) is the exposed surface area of the bar,
T, and Tw are the surface temperature of the bar and the water temperature,
respectively. The heat capacity of the bar is 0.46 J/(g °C). Heat conduction in iron
is rapid enough for the temperature T to be considered uniform throughout the bar.
a) Write an energy balance on the bar
b) Plot the expected plot of T, versus t and then curve fitting.
M = (60 cm')(7.7 g/cm') = 462 g
= 0.46 kJ/(kg.°C), T, = 25°C
%3D
C,
U = 0.050 J/(min - cm2.°C)
A = 2[(2)(3) + (2)(10) + (3)(10)]Jem?
= 112 cm2
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