An insulating sphere of radius R = 3 cm has positive charge uniformly distributed throughout its entire volume. The electric field at the surface of the sphere has a magnitude of E = 5x107 V/m (a) [3 points] Calculate the volumetric charge density p of the sphere (in C/m3) and Calculate the magnitude of the electric field at a point located atr= 1cm, inside the insulator.

Suppose we have a charge, q1=1 μC. This charge makes an electric field some distance r=73 cm away from it. Now suppose our measurement of q1 is only accurate to within 0.2 μC, and our measurement of r is only accurate to within 1.5 cm. What is the uncertainty in our field calculation due only to the uncertainty in the charge separation r? My answer for this was 694.05 N/C which was wrong

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Two oppositely charged but otherwise identical conducting plates of area 2.50 square centimeters are separated by a dielectric 1.80 millimeters thick, with a dielectric constant of K = 3.60. The I can't found part c resultant electric field in the dielectric is 1.20 x 10° volts per meter. Part A Compute the magnitude of the charge per unit area o on the conducting plate. Express your answer in coulombs per square meter to three significant figures. • View Available Hint(s) o = 3.82x10-5 C/m² Submit Previous Answers Correct Part B Compute the magnitude of the charge per unit area o1 on the surfaces of the dielectric. Express your answer using three significant figures. • View Available Hint(s) ơ1 = 2.76x10-5 C/m² Submit Previous Answers Correct Note that the charges on the dielectric will be polarized to counteract the charges (and electric field) created by the capacitor. For example, near the positive surface of the capacitor the dielectric will have a negative charge. However, this…