An initial equilibrium mixture of methyl acetate, water and methyl alcohol contained 4.0 mL of methyl acetate, 3.0 mL of water, and 2.0 mL of methyl alcohol.  Final analysis showed that the solution required 12.15 mL of 0.5000 M NaOH for neutralization.  Calculate  Keq for this hydrolysis experiment.                                                CH3CO2CH3   +   H2O  <---->   CH3CO2H   +   CH3OH   Densities (g/mL):         0.9279                1.000                   1.0530            0.7866 Molar masses.              74.08                  18.01                     60.05             32.04         CH3CO2CH3   +   H2O  <---->   CH3CO2H   +   CH3OH

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A: Dissociation of weak acid: CH3COOH⇋CH3COO- + H+ Ka=CH3COO-H+CH3COOH

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Q: PRE-LAB QUESTIONS Calculate the volume, in mL, of a 0.50 M NaOH solution that will be required to…

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Q: This question concerns part 1 of this lab. You need to make a buffer solution by mixing both a weak…

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Q: None

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Q: How many ml of NaOH stock solution have been added to establish the buffer?

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Q: Hydrolysis constant of ammonium ( when Kw & Kb are chloride is 1x10-14 & 1.8 x10-5 respectively)

A: GIVEN : Kw = 1 * 10-14 Kb = 1.8 * 10-5

Q: Write the Henderson-Hasselbalch equation for a propanoic acid solution (CH,CH, CO, H, pK, = 4.874).

A: To solve this we have to we have to use the  Henderson–Hasselbalch equation of weak acid .

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A: The explanation for the following is:

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Applications of Molecular Spectroscopy

When light sources pass through the diffraction grating then light splits into different wavelengths. The light source produces two types of patterns that are shown as destructive and non-destructive. The light source is in the form of quanta that is quantitation.