An image is being formed by a mirror with a spherical radius of R=+40cm. Left side of room: Draw mirror spherical surface curving to the left! Draw mirror spherical surface curving to the right! Right side of room: Spherical Mirror Curving to the Right Spherical Mirror Curving to the Left Answer these questions / do these tasks first: 1) On which side of mirror is the sphere's center C? Draw C! Hint: Which way does your mirror curve? 2) Which side of the mirror is its outgoing side ? Mark it as "Out". Hint: Use C, the given sign of R (i.e., R>0) and the sign convention for R. 3) Which side of the mirror is its incoming side ? Mark it as "In". Hint: It's a mirror → incoming rays are reflected to produce outgoing rays. 4) On which side of mirror is the object being placed? Draw object as upright arrow. Hint: Use sign of d and sign convention for d. Then calculate d', m, h', for all d-values shown in the table below and do the following for each of these four d-values, d=15cm, d=25cm, d=40cm, d=60cm : 5) Draw the image on the correct side of the mirror: to the left or the right of mirror? Draw the image with the correct orientation: erect or inverted? Draw the image at the left or the right of object? rect position rel. to object: Hints: --Use the sign convention for d' and the "Out" marking from 2) to figure out where the image is located relative to the mirror: to the left or to the right? --Use the sign convention form to figure out how the image is oriented relative to the object: erect or inverted? --Use the relative magnitude of |d| and |d'| to figure out which is closer to the mirror: object or image? From that and from the positioning of object and image relative to the mirror, figure out whether the image is to the left or the right of the object. 3 ст 40 cm <--Note: R > 0 R= f=R/2= cm image image inverted virtual h' [cm] d [cm] d' [cm] or real? or erect? 5.0 10.0 15.0 dof, df 19.5 20.5 25.0 30.0 d=R --> 40.0 60.0 10000.0

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