An ice skater spins with her arms extended. When she pulls in her arms, her moment of inertia decreases and her rate of spin (angular velocity w) increases. From the information provided below, find her final angular velocity. (Assume her total angular momentum is conserved.) Initial Final I = 4.38.kg-m? I = 0.47_kg-m? wi = 0.63_rev/s Wp = 5.65 rev/s 6.59 rev/s С. А. D. 5.871 rev/s 6.129 rev/s 6.895 rev/s В. Е. 6.403_rev/s F.

A particle is acted on by two torques about the origin: 7₁ has a magnitude of 3.7 N-m and is directed in the positive direction of the x axis, and 72 has a magnitude of 5.2 N-m and is directed in the negative direction of the y axis. In unit-vector notation, find de Idt, where is the angular momentum of the particle about the origin. Number i i ĴUnits

4. A skater has a moment of inertia of 105.0 kg.m² when his arms are outstretched and a moment of inertia of 64.0 kg.m² when his arms are tucked in close to his chest. If he starts to spin at an angular speed of 80.0 rpm (revolutions per minute) with his arms outstretched, what will his angular speed be when they are tucked in? rpm

Modem wind turbines generate electricity from wind power. The large, massive blades have a large moment of inertia and carry a great amount of angular momentum when rotatingA wind turbine has a total of 3 bladesEach blade has a mass of m 5500 kg distributed uniformly along its length and extends a distance r = 49m from the center of rotationThe turbine rotates with a frequency of f= 15 rpm. Part a: enter expression for the total moment of inertia of the wind turbine about its a is of rotation in terms of the define quantites Part b calcukate the total moment of inertia of the wijd turbine about its axis in units of kilogram meter square Part c enter an expression for the expression for the angular momentum of the wind turbine in terms of the defined quantities Part d : calculate the angular momentum of rhe wind turnine in units if kilogram meters squared per second

A bicycle wheel, of mass 1.52 kg is placed at the end of a rod 0.630 m in length, which can pivot freely about the other end. D- The rod is of negligble mass. The wheel is turning rapidly such that it has an angular momentum of 15.1 kgm2/s. At what angular speed does the wheel revolve horizontally about the pivot? Submit Answer Tries 0/10

A small Particle of mass 50 gram fired horizontally at a speed of 8 m/s . When it collides and embedded to the edge of a uniform solid cylinder who is initially at rest, the cylinder rotates freely about its axis through its center perpendicular to the page. If the cylinder has a mass of 0.6 kg and a radius of 20 cm, How much kinetic energy is lost in the collision? After Before O A. 1.4 J OB. 2.8 J О С. 3.2 J O D. 4.4 J O E. 1J

A circular disk has a rotational inertia of 9.1 kg.m² and a constant angular acceleration of 8.1 rad/s2. If it starts from rest the work done during the first 2.7 s by the net torque acting on it is: Select one: a. 2176.25 ] Ob.8705.00 1 C. 4352.50 k] d. 4352.50 ]