
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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An eye is corrected by a -5.50D lens, 2.0 cm from the
eye. (a) Is this eye near- or farsighted? (b) What is this
eye’s far point without glasses?
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- A person is nearsighted, and the relaxed eye focuses at a distance of 50 cm. What is the strength of the desired corrective lens in diopters? thats the full questionarrow_forwardA simple refracting telescope with an objective lens with focal length 2.00m and and eye piece of with focal length of 2.0 cm is used to view Mars when it is 6 x 107km from the Earth. For the purposes of this question assume the unaided human eye can resolve objects 0.002 radians apart, what feature size can be seen on Mars with telescope? For the purpose of his problem assume that the diameter of the telescope is sufficiently large that diffraction does not play a role. o 2400 km o 1200 km o 3600 km o 120 kmarrow_forwardAn object and an image screen are separated by 50 cm. There are two locations betweenthem where a thin lens with f = 8 cm can be placed so that a focused image forms on thescreen. Find the two positions.arrow_forward
- A far-sighted person has a near point of 1.75 m. What is the refracting power of contact lensesthat would correct their vision, resulting in a near point of 0.25 m?arrow_forwardA compound microscope is made from an objective lens of focal length fo = 8 mm, andan eyepiece of fe = 12 mm. The objective lens is moved close to the object so that anintermediate image is formed 20 cm above the objective lens; then the eyepiece is set atits own focal length above the intermediate image, forming a virtual image at infinity forthe user’s eye. If the object is 0.15 mm in diameter, calculate the following, taking care todefine symbols used:i) The required distance of the objective lens above the object.ii) The diameter of the intermediate image.iii) The angular size of the image to the user’s eye.iv) The system angular magnification, defined as the angular size in (iii) divided by theangle subtended by the object to the naked eye from a distance of 25 cm.arrow_forwardA nearsighted man wears contact lenses of -3.00 diopters. With these lenses, his corrected near point is 25.0 cm. What is his uncorrected near point?arrow_forward
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