An experiment involves the rxn: 2HI(g) ⇄ H2(g) + I2(g). A sample of pure HI was placed inside a rigid container at a certain temperature. The table provides the initial and equilibrium concentrations for some of the substances in the rxn. Based on the data, which of the following is the value of the equilibrium constant (Keq) for the reaction, and why? Keq= 2.5×10−1, because [I2]eq = 2×[HI]eq. Keq= 6.3×10−2, because [I2]eq = ½ [HI]eq. Keq= 1.6×10−2, because [I2]eq = [H2]eq. Keq= 3.1×10−2, because [I2]eq = 2×[H2]eq.
An experiment involves the rxn: 2HI(g) ⇄ H2(g) + I2(g). A sample of pure HI was placed inside a rigid container at a certain temperature. The table provides the initial and equilibrium concentrations for some of the substances in the rxn. Based on the data, which of the following is the value of the equilibrium constant (Keq) for the reaction, and why? Keq= 2.5×10−1, because [I2]eq = 2×[HI]eq. Keq= 6.3×10−2, because [I2]eq = ½ [HI]eq. Keq= 1.6×10−2, because [I2]eq = [H2]eq. Keq= 3.1×10−2, because [I2]eq = 2×[H2]eq.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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An experiment involves the rxn: 2HI(g) ⇄ H2(g) + I2(g).
A sample of pure HI was placed inside a rigid container at a certain temperature. The table provides the initial and equilibrium concentrations for some of the substances in the rxn. Based on the data, which of the following is the value of the equilibrium constant (Keq) for the reaction, and why?
- Keq= 2.5×10−1, because [I2]eq = 2×[HI]eq.
- Keq= 6.3×10−2, because [I2]eq = ½ [HI]eq.
- Keq= 1.6×10−2, because [I2]eq = [H2]eq.
- Keq= 3.1×10−2, because [I2]eq = 2×[H2]eq.
Transcribed Image Text:2HI (g) + H2 (g) +2(g)
Equilibrium
Conc (M)
Sub-
Initial
stance Conc (M)
HI
0.30
0.24
H2
0.00
0.03
12
0.00
?
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