Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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**Problem: Finding the Equation of an Ellipse**

To find the equation of the ellipse depicted on the graph, we need to analyze the graph in the image.

**Graph Description:**
- The graph features a coordinate plane with an ellipse centered at the origin (0, 0).
- The x-axis and y-axis both range from -10 to 10.
- The ellipse is vertically oriented, meaning it is taller than it is wide.

**Ellipse Characteristics:**
- The semi-major axis (along the y-direction) extends from -5 to 5 on the y-axis, giving it a length of 10. Therefore, the length of the semi-major axis is 5.
- The semi-minor axis (along the x-direction) extends from -2 to 2 on the x-axis, giving it a length of 4. Therefore, the length of the semi-minor axis is 2.

**Equation Form:**
The equation of an ellipse centered at the origin, with a semi-major axis along the y-axis and a semi-minor axis along the x-axis, is given by:

\[
\frac{x^2}{b^2} + \frac{y^2}{a^2} = 1
\]

Where:
- \(a\) is the semi-major axis length (5).
- \(b\) is the semi-minor axis length (2).

**Plugging in the Values:**

\[
\frac{x^2}{2^2} + \frac{y^2}{5^2} = 1
\]

This simplifies to:

\[
\frac{x^2}{4} + \frac{y^2}{25} = 1
\]

Thus, the equation of the ellipse is:

\[
\frac{x^2}{4} + \frac{y^2}{25} = 1
\]
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Transcribed Image Text:**Problem: Finding the Equation of an Ellipse** To find the equation of the ellipse depicted on the graph, we need to analyze the graph in the image. **Graph Description:** - The graph features a coordinate plane with an ellipse centered at the origin (0, 0). - The x-axis and y-axis both range from -10 to 10. - The ellipse is vertically oriented, meaning it is taller than it is wide. **Ellipse Characteristics:** - The semi-major axis (along the y-direction) extends from -5 to 5 on the y-axis, giving it a length of 10. Therefore, the length of the semi-major axis is 5. - The semi-minor axis (along the x-direction) extends from -2 to 2 on the x-axis, giving it a length of 4. Therefore, the length of the semi-minor axis is 2. **Equation Form:** The equation of an ellipse centered at the origin, with a semi-major axis along the y-axis and a semi-minor axis along the x-axis, is given by: \[ \frac{x^2}{b^2} + \frac{y^2}{a^2} = 1 \] Where: - \(a\) is the semi-major axis length (5). - \(b\) is the semi-minor axis length (2). **Plugging in the Values:** \[ \frac{x^2}{2^2} + \frac{y^2}{5^2} = 1 \] This simplifies to: \[ \frac{x^2}{4} + \frac{y^2}{25} = 1 \] Thus, the equation of the ellipse is: \[ \frac{x^2}{4} + \frac{y^2}{25} = 1 \]
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