MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- According to a recent study, the carapace length for adult males of a certain species of tarantula are normally distributed with a mean of u = 17.44 mm and a standard deviation of a = 1.72 mm. Complete parts (a) through (d) below. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a. Find the percentage of the tarantulas that have a carapace length between 15 mm and 16 mm. The percentage of the tarantulas that have a carapace length between 15 and 16 is 12.27 %. (Type an integer or decimal rounded to two decimal places as needed.) correct: 1 b. Find the percentage of the tarantulas that have a carapace length exceeding 18 mm. The percentage of the tarantulas that have a carapace length exceeding 18 is%. (Type an integer or decimal rounded to two decimal places as needed.) E S D R F T ^ 6 G Y & 7 H U * 8 J DI FB 1 ( 9 K DD F9 0 0 L F10 P : + 11 = 11arrow_forwardA lawyer commutes daily from his suburban home to his midtown office. The average time for a one-way trip is 24 minutes, with a standard deviation of 3.4 minutes. Assume the distribution of trip times to be normally distributed. Complete parts (a) through (e) below. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. 1 hour? (a) What is the probability that a trip will take at least (Round to four decimal places as needed.)arrow_forwardhow to solve this ?arrow_forward
- An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 150 lb and 191 lb. The new population of pilots has normally distributed weights with a mean of 160 lb and a standard deviation of 33.3 lb. Click here to view page 1 of the standard normal distribution. Click here to view page 2 of the standard normal distribution. ne nent a. If a pilot is randomly selected, find the probability that his weight is between 150 lb and 191 Ib. The probability is approximately (Round to four decimal places as needed.)arrow_forwardAccording to a recent study, the carapace length for adult males of a certain species of tarantula are normally distributed with a mean of u = 17.08 mm and a standard deviation of o = 1.57 mm. Complete parts (a) through (d) below. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a. Find the percentage of the tarantulas that have a carapace length between 15 mm and 16 mm. The percentage of the tarantulas that have a carapace length between 15 and 16 is (Type an integer or decimal rounded to two decimal places as needed.) %.arrow_forwardAn engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 120 o and 161 lb. The new population of pilots has normally distributed weights with a mean of 129 lb and a standard deviation of 27.1 Ib. Click here to view page 1 of the standard normal distribution. Click here to view page 2 of the standard normal distribution. a. If a pilot is randomly selected, find the probability that his weight is between 120 Ib and 161 lb. The probability is approximately (Round to four decimal places as needed.)arrow_forward
- An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 120 lb and 161 Ib. The new population of pilots has normally distributed weights with a mean of 127 Ib and a standard deviation of 30.7 Ib. Click here to view page 1 of the standard normal distribution. Click here to view page 2 of the standard normal distribution. a. If a pilot is randomly selected, find the probability that his weight is between 120 Ilb and 161 Ib. The probability is approximately 0.4575 . (Round to four decimal places as needed.) > b. If 36 different pilots are randomly selected, find the probability that their mean weight is between 120 lb and 161 Ib. The probability is approximately- (Round to four decimal places as needed.) > Enter your answer in the answer box and then click Check Answer. Clear All Check Answer part remaining P Pearson Copyright © 2021 Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy I Permissions |…arrow_forwardPlease show your work. thank youarrow_forwardAn engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 130 lb and 181 Ib. The new population of pilots has normally distributed weights with a mean of 136 Ib and a standard deviation of 26.1 lb. Click here to view page 1 of the standard normal distribution. Click here to view page 2 of the standard normal distribution. a. If a pilot is randomly selected, find the probability that his weight is between 130 Ib and 181 Ib. The probability is approximately 0.5486. (Round to four decimal places as needed.) b. If 38 different pilots are randomly selected, find the probability that their mean weight is between 130 Ib and 181 Ib. The probability is approximately (Round to four decimal places as needed.)arrow_forward
- An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 120 Ib and 161 Ib. The new population of pilots has normally distributed weights with a mean of 125 lb and a standard deviation of 26.8 Ib. Click here to view page 1 of the standard normal distribution. Click here to view page 2 of the standard normal distribution. a. If a pilot is randomly selected, find the probability that his weight is between 120 lb and 161 Ib. The probability is approximately 0.4844 . (Round to four decimal places as needed.) b. If 30 different pilots are randomly selected, find the probability that their mean weight is between 120 Ib and 161 lb. The probability is approximately (Round to four decimal places as needed.)arrow_forwardIn a recent study, the distances of certain raptor nests to the nearest marshland were studied. The study found that these distances are normally distributed with mean 4.52 km and standard deviation 0.85 km. Let Y be the distance of a randomly selected nest to the nearest marshland. Complete parts (a) and (b). Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a. Determine P(Y > 5). P(Y > 5) = (Round to four decimal places as needed.)arrow_forward
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