An elevator shown below filled with passengers has a mass of 1.7 103 kg. The elevator does motions (a) through (c) in succession. meg Owe back. For each of the parts below draw a free body diagram of the elevator in your notebook for each of the parts (a) to (c). Draw the acceleration and velocity vectors in the boxes. For each part, are the vectors for tension in the string and weight of the elevator of equal lengths or unequal lengths. "L ME a (a) The elevator accelerates upward from rest at a rate of 1.4 quantities are correct to 3 significant figures. (i) Newton's Second Law in the y-direction can be written as: Instruction: If a is the magnitude of the acceleration, pick "1" if the acceleration is upward pick "-1" if the acceleration is downwards, and pick "0" if there is no acceleration. ZF, T-m,g= xma (ii) Calculate the tension in the cable supporting the elevator. Enter to 3 significant figures T= ✔N (iii) How high has the elevator moved during this time? Enter to 3 significant figures Ay= ✔m (iv) Calculate the velocity of the elevator after this time. Enter to 3 significant figures v(t = 1.5 s) = (b) The elevator continues upward at constant velocity for 8.15 s. Assume that all quantities are correct to 3 significant figures. (i) Newton's Law in the y-direction can be written as: Instruction: If a is the magnitude of the acceleration, pick "1" if the acceleration is upward pick "-1" if the acceleration is downwards, and pick "0" if there is no acceleration. ✓ for 1.5 s. Assume that all m S ZF, T-mog= x ma (ii) Calculate the tension in the cable supporting the elevator.
An elevator shown below filled with passengers has a mass of 1.7 103 kg. The elevator does motions (a) through (c) in succession. meg Owe back. For each of the parts below draw a free body diagram of the elevator in your notebook for each of the parts (a) to (c). Draw the acceleration and velocity vectors in the boxes. For each part, are the vectors for tension in the string and weight of the elevator of equal lengths or unequal lengths. "L ME a (a) The elevator accelerates upward from rest at a rate of 1.4 quantities are correct to 3 significant figures. (i) Newton's Second Law in the y-direction can be written as: Instruction: If a is the magnitude of the acceleration, pick "1" if the acceleration is upward pick "-1" if the acceleration is downwards, and pick "0" if there is no acceleration. ZF, T-m,g= xma (ii) Calculate the tension in the cable supporting the elevator. Enter to 3 significant figures T= ✔N (iii) How high has the elevator moved during this time? Enter to 3 significant figures Ay= ✔m (iv) Calculate the velocity of the elevator after this time. Enter to 3 significant figures v(t = 1.5 s) = (b) The elevator continues upward at constant velocity for 8.15 s. Assume that all quantities are correct to 3 significant figures. (i) Newton's Law in the y-direction can be written as: Instruction: If a is the magnitude of the acceleration, pick "1" if the acceleration is upward pick "-1" if the acceleration is downwards, and pick "0" if there is no acceleration. ✓ for 1.5 s. Assume that all m S ZF, T-mog= x ma (ii) Calculate the tension in the cable supporting the elevator.
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