An electron moving parallel to the x axis has an initial speed of 5.06 x 10° m/s at the origin. Its speed is reduced to 1.28 x 105 m/s at the point x = 2.00 cm. %3D (a) Calculate the electric potential difference between the origin and that point. Volts (b) Which point is at the higher potential? both have the same potential the point x = 2.00 cm the origin

Answer the following question given the position and charge of three charged objects. q1 = 2nC (-2,3), q2 = -5nC (1,3), and q3 = -2nC (0,0). What is the electric potential at (6,6)? a. -23.14 V b. 12.29 V c. -7.73 V d. 1.22 V Please provide the complete solution.

Two charged particles create an electric potential, and everywhere in the xy-plane this potential is described by the following function. 32.0 V 50.0 V √(x + 1.18 m)² + y² x² + (y - 2.30 m)² Determine the charge and coordinates for the position of the two particles. Give the charge (in nC) and coordinates (in m) for the position of the particle responsible for the first term first. first term 91 = X = 92 = V = y = Give the charge (in nC) and coordinates (in m) for the position of the particle responsible for the second term. X = y = nC m m nC 3 3 8 m

= In the figure point P is at the center of the rectangle. With V = 0 at infinity, q₁ = 5.90 fC, 92 - 4.09fC, 93 = 4.83 fC, and d = 3.38 cm, what is the net electric potential in volts at P due to the six charged particles? Number i Units +9₁ +93 •P -92 -d ·d -93 +91