An electron moves with a speed of 5.0 × 104 m/s perpendicular to a uniform magnetic field of magnitude 0.20 T. What is the magnitude of the magnetic force on the electron? (e = 1.60 × 10-19 C). Hint: F = g(Vx B) = gVB Sine, where e is the angle between the direction of the B and V
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![An electron moves with a speed of 5.0 x 104 m/s perpendicular to a uniform magnetic field of magnitude 0.20 T. What is the magnitude of the
magnetic force on the electron? (e = 1.60 × 10-19 C).
Hint: F = q(Vx B) = qVB Sine, where e is the angle between the direction of the B and V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F31330aa5-a64b-4d2f-80e6-6ea74abb2a34%2F326b35b0-1dca-48eb-bb4b-d665164a6a31%2Fmb87dz_processed.png&w=3840&q=75)
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