An electron moves with a speed of 5.0 × 104 m/s perpendicular to a uniform magnetic field of magnitude 0.20 T. What is the magnitude of the magnetic force on the electron? (e = 1.60 × 10-19 C). Hint: F = g(Vx B) = gVB Sine, where e is the angle between the direction of the B and V

A proton moves with a speed of 207258 m/s. It is traveling in the x y plane. A magnetic field of 2.1 mT is pointing in the z-direction. What is the radius (in meters) of the circular path this proton will follow?

A 45.1 C charge is moving with a velocity of 39.6 m/s in the +x-direction. A magnetic field of 89 T is point in the -x-direction. What is the force (in N) on this charge?

A particle with charge 7.30 x 10^-6 C moves at 3.00 x 10^6 m/s through a magnetic field of strength 2.52 T. The angle between the particles velocity and the magnetic field direction is 53.0 degrees and the particle undergoes an acceleration of 6.8 m/s^2. What is the particles mass?       6.48 kg     2.7 kg     5.4 kg     8.8 kg

A wire of length t = 0.75 m is conducting a current of %3D i = 7.5 A toward the top of the page and through a B = 3.0 T %3D %3D uniform magnetic field directed into the page, as shown in the figure. What is the magnitude F of the magnetic force on the wire? F = What is the direction of the magnetic force on the wire? O right O out of the screen O up O left O down O into the screen

In an experiment designed to measure the magnitude of a uniform magnetic field, electrons are accelerated from rest through a potential difference of 350 V and then enter a uniform magnetic field that is perpendicular to the velocity vector of the electrons. The electrons travel along a curved path because of the magnetic force exerted on them, and the radius of the path is measured to be 7.5 cm. What is the magnitude of the magnetic field? me= 9.11× 10-31 kg, charge of electron is 1.6× 10-19 C a) 3.3 × 10-4 b) 4.8 × 10-4 c) 6.4 × 10-4 d) 8.4 × 10-4 e) 8.5 × 10-4

A proton is moving in positive x-direction with the speed of 3.2x10^5 m/s. It enters in a uniform magnetic field of 8.0-mT pointing into the page. What is the radius of the path this proton will follow in the magnetic field. (e = 1.60 × 10-19 C, M (proton) = 1.67X10^-27 kg). 8.2 m O 0.062 m 0.19 m 0.42 m

A particle with mass 0.8 gram and charge .02 μC is moving in the x-y plane with a velocity v(t) given by the formula v(t) = (15000 i + 30000 j )m/s. It enters a region of space where a magnetic field B exists, given by B = (1.5 i + 2j) T. What is the force on the charge? (Hint: i, j and k are the unit vectors along x, y and z-axis respectively. Use the relationships i x i = j x j  =  k x k  = 0, and i x j  = k, etc.) a) .0003 N along positive z b) .0003 N along positive x                           c) .0003 N along negative z.   What is its acceleration? 0.375 m/s2 along negative z    b) 0.375 m/s2 along positive x              c) 0.375 m/s2 along positive z

= = 7. A proton is moving through a magnetic field in a direction perpendicular to the field as shown below. The magnetic field has a magnitude of B 0.13 T and the charge experiences a force of F 9.98 × 10-¹4 N. How fast and in what direction is it moving? The charge of a proton is qp +1.6 × 10-1⁹ C. = B (+

A duck flying due east passes over Atlanta, where the magnetic field of the Earth is 5.7 × 10−5 T directed north. The duck has a positive charge of 4.0 × 10−8 C. If the magnetic force acting on the duck is 3.40×10−11 N upward, what is the magnitude of the duck’s velocity? Answer in units of m/s.