An electron moves with a speed of 5.0 × 104 m/s perpendicular to a uniform magnetic field of magnitude 0.20 T. What is the magnitude of the magnetic force on the electron? (e = 1.60 × 10-19 C). Hint: F = g(Vx B) = gVB Sine, where e is the angle between the direction of the B and V

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An electron moves with a speed of 5.0 x 104 m/s perpendicular to a uniform magnetic field of magnitude 0.20 T. What is the magnitude of the
magnetic force on the electron? (e = 1.60 × 10-19 C).
Hint: F = q(Vx B) = qVB Sine, where e is the angle between the direction of the B and V
Transcribed Image Text:An electron moves with a speed of 5.0 x 104 m/s perpendicular to a uniform magnetic field of magnitude 0.20 T. What is the magnitude of the magnetic force on the electron? (e = 1.60 × 10-19 C). Hint: F = q(Vx B) = qVB Sine, where e is the angle between the direction of the B and V
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