An electron moves in a circular path perpendicular to a constant magnetic field with a magnitude of 2.00 mT. The angular momentum of the electron about the center of the circle is 3.00 ✕ 10-25 J·s. (a) Determine the radius of the circular path. (b) Determine the speed of the electron.

An alpha-particle (m = 6.64·10−27 kg; q = 3.2·10−19 C) travels in a circular path of radius 28 cm in a uniform magnetic field of magnitude 1.3 T. (a) What is the speed of the particle? (b) What is the kinetic energy in electron-volts? (c) Through what potential difference must the particle be accelerated in order to give it this kinetic energy?

An electron moves with a velocity of 10^7 m/s in the x-y plane at an angle of 45∘ to both the +x and +y axes. There is a magnetic field of 2.0 T in the +y direction.1)Determine the magnitude of the magnetic force on the electron. (Express your answer using two significant figures.)

An electron moves in a circular path perpendicular to a constant magnetic field with a magnitude of 4.00 mT. The angular momentum of the electron about the center of the circle is 6.00 x 10-25 1.s. (a) Determine the radius of the circular path. cm (b) Determine the speed of the electron. m/s

Please help me answer this question. An electron moves at a speed of 8 x 10*5 m/s in a direction perpendicular to a field Magnetic uniform of 0.30 T. The magnetic force exerted on the electron is:

What uniform magnetic field, applied perpendicular to a beam of electrons moving at 2.70 ✕ 106 m/s, is required to make the electrons travel in a circular arc of radius 0.400 m?

An electron in a magnetic field moves along a circle with a radius of 25.4 m with a speed that follows: v(t)=V0e−bt where b = 0.56 s-1and V0 = 170 m/s. I need to find the angular acceleration at t=3.7s, but I don't know how I'm supposed to get that becuase the formula that we have says that it is the second derivative of angular position, but when I calculate angular position all I get is 6.57516 radians. I don't understand how I'm supposed to take a derivative of that since it doesn't have any variables.  I don't know if it is needed for this, but I already calculated the centripetal acceleration as 18.0446m/s^2

A charged particle moves with a speed of 6.0×103 m/s perpendicularly into an uniform magnetic field of magnitude 0.20 T.  The charge of the particle is 5.8 ×10-16 C, mass of the particle is 1.2 ×10-21kg. (a) What is the magnitude of the magnetic force on the particle?  (b) What could be the radius of the path of the particle if it moves inside the B-field?(c) To avoid the particle being deflected by the magnetic field, (so particle can move straight through the B-field,) an electric field is applied at the same location. What is the magnitude of the E-field? HTML EditorKeyboard Shortcuts