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**Educational Exercise: Photon Emission by an Electron**

**Problem Statement:**

An electron (\( m = 511 \, \text{keV}/c^2 \)) is moving at \( 0.020c \) when it collides with a metal target. The electron loses exactly half its kinetic energy and emits a photon. Use the canvas to illustrate the process. Neglect the effects of relativity and use \( hc = 1.240 \, \text{keV nm} \) to show how to find the wavelength of the photon.

**Instructions:**

1. **Conceptual Understanding:**
   - Determine the initial kinetic energy of the electron.
   - Calculate the energy lost by the electron as it emits the photon.
   - Use the energy-wavelength relationship to find the wavelength of the emitted photon.

2. **Assumptions:**
   - Effects of relativity are neglected.
   - The value of \( hc \) is given as \( 1.240 \, \text{keV nm} \).

3. **Formulas:**
   - Kinetic Energy (KE): \( \text{KE} = \frac{1}{2}mv^2 \)
   - Energy-Wavelength relationship: \( E = \frac{hc}{\lambda} \)

4. **Calculation Steps:**
   - Calculate the kinetic energy of the electron before collision.
   - Determine the energy of the photon using the given \( hc \) value.
   - Solve for the wavelength \( \lambda \).

**Interactive Components:**
- Use the provided canvas to draw diagrams illustrating energy transfer.
- Include labeled components showing initial and final states.

**Submit your calculations and illustration for review.**

**Discussion Section:**
- Discuss how neglecting relativity might affect the results.
- Explore practical applications of photon emission in technology.

**Feedback Mechanism:**
- Interactive quizzes to test understanding of key concepts.
- Summary notes available for download after completion. 

---

**Graphical/Diagram Explanation:**
- The image lacks graphs or detailed diagrams. Consider using diagrams to visualize the process as needed.
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Transcribed Image Text:**Educational Exercise: Photon Emission by an Electron** **Problem Statement:** An electron (\( m = 511 \, \text{keV}/c^2 \)) is moving at \( 0.020c \) when it collides with a metal target. The electron loses exactly half its kinetic energy and emits a photon. Use the canvas to illustrate the process. Neglect the effects of relativity and use \( hc = 1.240 \, \text{keV nm} \) to show how to find the wavelength of the photon. **Instructions:** 1. **Conceptual Understanding:** - Determine the initial kinetic energy of the electron. - Calculate the energy lost by the electron as it emits the photon. - Use the energy-wavelength relationship to find the wavelength of the emitted photon. 2. **Assumptions:** - Effects of relativity are neglected. - The value of \( hc \) is given as \( 1.240 \, \text{keV nm} \). 3. **Formulas:** - Kinetic Energy (KE): \( \text{KE} = \frac{1}{2}mv^2 \) - Energy-Wavelength relationship: \( E = \frac{hc}{\lambda} \) 4. **Calculation Steps:** - Calculate the kinetic energy of the electron before collision. - Determine the energy of the photon using the given \( hc \) value. - Solve for the wavelength \( \lambda \). **Interactive Components:** - Use the provided canvas to draw diagrams illustrating energy transfer. - Include labeled components showing initial and final states. **Submit your calculations and illustration for review.** **Discussion Section:** - Discuss how neglecting relativity might affect the results. - Explore practical applications of photon emission in technology. **Feedback Mechanism:** - Interactive quizzes to test understanding of key concepts. - Summary notes available for download after completion. --- **Graphical/Diagram Explanation:** - The image lacks graphs or detailed diagrams. Consider using diagrams to visualize the process as needed.
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