Gg ▼Part AAn electron is to be accelerated from a velocity of 1.50x106 m/s to a velocity of 9.00x106 m/s. Through what potential difference must the electron pass to accomplish this?Vinitial - Vfinal = -224 VSubmit✓ CorrectSet Up: Apply conservation of energy, Eq. (18.3). Use Eq. (18.10) to express U in terms of V.Solve: K₁+qV₁ = K₂ +qV₂Previous Answersq(V₁ V₂) = K2 - K₁iq=-1.602 × 10-¹⁹ CK₁ = mv² = 3.69 × 10-¹7J; K₂ = 1/mev² = 1.02 × 10-¹8 JV₁ V₂ =K₂-K₁9Reflect: The electron gains kinetic energy when it moves to higher potential.Part B-= -224VThrough what potential difference must the electron pass if it is to be slowed from 9.00x106 m/s to a halt?Vinitial - Vfinal =1971 ΑΣΦ- 172.76Submit Previous Answers Request AnswerX Incorrect; Try Again; 8 attempts remaining?V

For Part(a):Initial velocity of electron is Final velocity of electron is Note:Charge on electron is…

Answered: An electron is to be accelerated from a…

An electron is to be accelerated from a velocity of 1.50x105 m/s to a velocity of 9.00x105 m/s. Through what potential difference must the electron pass to accomplish this?

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ISBN:9781305952300

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Chapter1: Units, Trigonometry. And Vectors

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Question

▼
Part A
An electron is to be accelerated from a velocity of 1.50x106 m/s to a velocity of 9.00x106 m/s. Through what potential difference must the electron pass to accomplish this?
Vinitial - Vfinal = -224 V
Submit
✓ Correct
Set Up: Apply conservation of energy, Eq. (18.3). Use Eq. (18.10) to express U in terms of V.
Solve: K₁+qV₁ = K₂ +qV₂
Previous Answers
q(V₁ V₂) = K2 - K₁iq=-1.602 × 10-¹⁹ C
K₁ = mv² = 3.69 × 10-¹7J; K₂ = 1/mev² = 1.02 × 10-¹8 J
V₁ V₂ =
K₂-K₁
9
Reflect: The electron gains kinetic energy when it moves to higher potential.
Part B
-
= -224V
Through what potential difference must the electron pass if it is to be slowed from 9.00x106 m/s to a halt?
Vinitial - Vfinal =
1971 ΑΣΦ
- 172.76
Submit Previous Answers Request Answer
X Incorrect; Try Again; 8 attempts remaining
?
V

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Step 1: Given data

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Step 2: Define Kinetic energy.

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Step 3: Using conservation of energy, obtaining the expression for potential difference.

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Step 4: Calculation for potential difference for part(a).

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Step 5: Calculation for potential difference for part(a).

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