An electron is accelerated from rest by a potential difference of 0.20 V. How much greater would its final speed be if it is accelerated with four times as much voltage? Explain

Calculate the speed of a proton that is accelerated from rest through an electric potential difference of 130 V.m/s? (b) Calculate the speed of an electron that is accelerated through the same potential difference.

What potential difference is needed to accelerate a He ion (charge +e, mass 4 u) from rest to a speed of 1.5×106 m/s Express answer in volts.

A proton enters a parallel plate system moving with an initial velocity of 9413.1 m/s perpendicular to the electric field. The proton enters at the the positive plate and the electric field between the plates moves it in the direction of the negative plate. The plate separation distance is 19.2 cm and the potential difference between the plates is 1.9 V. What is the magnitude of the final velocity of the proton when it hits the negative plate? ( Please state what kinematics formula was used to find final velocity through the steps.)