An electron absorbs a single photon with a wavelength = 127 nm. Calculate the energy of the photon. O 1.56 x 1032 J O 1.56 x 10-18 J O 1.56 x 10-27 J O 6.39 × 10-26 j

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An electron absorbs a single photon with a wavelength = 127 nm. Calculate the energy of the photon.

**Question:** An electron absorbs a single photon with a wavelength = 127 nm. Calculate the energy of the photon.

**Options:**

- ○ 1.56 × 10³² J
- ○ 1.56 × 10⁻¹⁸ J
- ○ 1.56 × 10⁻²⁷ J
- ○ 6.39 × 10⁻²⁶ J

**Explanation:**

To calculate the energy of a photon, you can use the formula:

\[ E = \frac{hc}{\lambda} \]

Where:
- \( E \) is the energy,
- \( h \) is Planck's constant (\(6.626 \times 10^{-34} \, \text{J}\cdot\text{s}\)),
- \( c \) is the speed of light (\(3.00 \times 10^8 \, \text{m/s}\)),
- \( \lambda \) is the wavelength (\(127 \, \text{nm} = 127 \times 10^{-9} \, \text{m}\)).

Substituting the known values:

\[ E = \frac{(6.626 \times 10^{-34} \, \text{J}\cdot\text{s})(3.00 \times 10^8 \, \text{m/s})}{127 \times 10^{-9} \, \text{m}} \]

By calculating, you should match one of the given options.
Transcribed Image Text:**Question:** An electron absorbs a single photon with a wavelength = 127 nm. Calculate the energy of the photon. **Options:** - ○ 1.56 × 10³² J - ○ 1.56 × 10⁻¹⁸ J - ○ 1.56 × 10⁻²⁷ J - ○ 6.39 × 10⁻²⁶ J **Explanation:** To calculate the energy of a photon, you can use the formula: \[ E = \frac{hc}{\lambda} \] Where: - \( E \) is the energy, - \( h \) is Planck's constant (\(6.626 \times 10^{-34} \, \text{J}\cdot\text{s}\)), - \( c \) is the speed of light (\(3.00 \times 10^8 \, \text{m/s}\)), - \( \lambda \) is the wavelength (\(127 \, \text{nm} = 127 \times 10^{-9} \, \text{m}\)). Substituting the known values: \[ E = \frac{(6.626 \times 10^{-34} \, \text{J}\cdot\text{s})(3.00 \times 10^8 \, \text{m/s})}{127 \times 10^{-9} \, \text{m}} \] By calculating, you should match one of the given options.
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