An electromagnet lift system is shown in Fig. P3.5. The coil has 2500 turns. The flux density in the air gap is 1.25 T. Assume that the core material is ideal. (a) For an air gap, g = 10 mm: (i) Determine the coil current. (ii) Determine the energy stored in the magnetic system. (iii) Determine the force on the load (sheet of steel). (iv) Determine the mass of the load (acceleration due to gravity = 9.81 m/sec²). (b) If the air gap is 2 mm, determine the coil current required to lift the load.
An electromagnet lift system is shown in Fig. P3.5. The coil has 2500 turns. The flux density in the air gap is 1.25 T. Assume that the core material is ideal. (a) For an air gap, g = 10 mm: (i) Determine the coil current. (ii) Determine the energy stored in the magnetic system. (iii) Determine the force on the load (sheet of steel). (iv) Determine the mass of the load (acceleration due to gravity = 9.81 m/sec²). (b) If the air gap is 2 mm, determine the coil current required to lift the load.
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
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Publisher:Robert L. Boylestad
Chapter1: Introduction
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Step 1: Summarize the given details
VIEWStep 2: Calculate the coil current
VIEWStep 3: Calculate the energy stored in the magnetic system
VIEWStep 4: Calculate the Force on the load
VIEWStep 5: Calculate the mass of the load
VIEWStep 6: Calculate the coil current when the air gap length is 2mm
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