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Transcribed Image Text:An electromagnet in the shape of a horseshoe has a coil with N turns. The coil carries a current I. The cross section of the horseshoe is A. Suppose that you are holding the electromagnet on top of a
small bar laying flat on a desk. The bar is made of the same material as the electromagnet core. The field between one of the horseshop poles and the bar is
NI
H=-
2z
where z is the air gap space between the poles of the electromagnet and the bar. Recall that
F=- VW
Determine the magnitude of the force that the electromagnet exerts on the bar as a function of the gap spacing z.
O a.
O b. NI
F=
2z
OC.
O d.
Fedo AI
0
F = μ₁
F = μ
A
0
- (NI) 2
A
1/2 (N₁) ²
4z²
A
5 (NI) ²
8z²
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