An electric charge q1 moving with the velocity v1 produces a magnetic field B given by Orl r2 В where î points from q1 to the point at which B is measured (Biot-Savart law, (a) Show that the magnetic force F12 on a second charge q2, velocity v2 due to the first one, is given by the triple product lo 9192 F12 = 4T r2 Üz × (01 × î).

An electron is traveling with a constan velocity vo in the presence of a uniform electric mg field E-Ek, where E- e (Here, m denotes the mass of the electron and e denotes its charge. g denotes the acceleration due to gravity). Gravity acts in the -Z direction. At t=0, when the electron is at the origin, a uniform magnetic field BB+BJ is switched on. Here. B, and B, are fixed positive BB. The coordinates of the point where the electron intersects the X-Y plane constants and B for the first time after t=0 are given by: 2amy B Zamy BB e (A) (C) 2 e B 2AMY, B B (B) (D) 2amv, B.B. e B 2rum BB B Lamy B.B B 2am B B

A wire arrying 18 amps in the z direction through a magnetic field with an x component of 0.19 T, a y component of 0.21 T, and a z component of 2.9 T.  What is the magnitude of the force on a 9 meter segment of wire?  answer in N.

An electron in a magnetic field moves along a circle with a radius of 25.4 m with a speed that follows: v(t)=V0e−bt where b = 0.56 s-1and V0 = 170 m/s. I need to find the angular acceleration at t=3.7s, but I don't know how I'm supposed to get that becuase the formula that we have says that it is the second derivative of angular position, but when I calculate angular position all I get is 6.57516 radians. I don't understand how I'm supposed to take a derivative of that since it doesn't have any variables.  I don't know if it is needed for this, but I already calculated the centripetal acceleration as 18.0446m/s^2

What is the strength of the magnetic field at the center of a circular loop of wire of diameter 7.14 cm when a current of 7.65 A flows in the wire? (μ0 = 4π × 10-7 T ∙ m/A) (Use π = 3.14). Express answers in milliTeslas.