A semicircular (radius = r) arc-shaped earrings. Is hung on the yarn pattern. Specify the encounter of the hanging wire and jewelry 90

Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter87: An Introduction To G- And M-codes For Cnc Programming
Section: Chapter Questions
Problem 22A
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Question
A semicircular (radius = r) arc-shaped earrings. Is hung on the yarn pattern. Specify
the encounter of the hanging wire and jewelry 90 <icy <180.
Tip: The task requires formulas for the curve (or focus) of the curve for the rules; e.g.
y
=
(Vast:
1
So
е
In what position is it worth calculating the length of the auxiliary triangle category?
122,5°,
y ds.
|
I
1
Transcribed Image Text:A semicircular (radius = r) arc-shaped earrings. Is hung on the yarn pattern. Specify the encounter of the hanging wire and jewelry 90 <icy <180. Tip: The task requires formulas for the curve (or focus) of the curve for the rules; e.g. y = (Vast: 1 So е In what position is it worth calculating the length of the auxiliary triangle category? 122,5°, y ds. | I 1
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Follow-up Question
An earring made of a homogeneous substance in the shape of a semicircle (radius = R) arc is hung
according to the thread pattern. Determine the meeting angle between the hanging wire and the
jewelry 90° < p < 180°
Hint: The problem requires formulas for the center of the curve (or center of gravity) for line
integrals; e.g.
y
=
1
е
Jo
y ds.
In which position should the length of the side of the auxiliary triangle be calculated?
(Answer: 122.5°)
|
|
Transcribed Image Text:An earring made of a homogeneous substance in the shape of a semicircle (radius = R) arc is hung according to the thread pattern. Determine the meeting angle between the hanging wire and the jewelry 90° < p < 180° Hint: The problem requires formulas for the center of the curve (or center of gravity) for line integrals; e.g. y = 1 е Jo y ds. In which position should the length of the side of the auxiliary triangle be calculated? (Answer: 122.5°) | |
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