College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- A hot-air balloon is drifting in level flight due east at 3.0 m/s due to a light wind. The pilot suddenly notices that the balloon must gain 20 m of altitude in order to clear the top of a hill 130 m to the east. How much time does the pilot have to make the altitude change without crashing into the hill? What minimum, constant, upward acceleration is needed in order to clear the hill?arrow_forward(a) What is the magnitude of the average acceleration of a skier who, starting from rest, reaches a speed of 10.7 m/s when going down a slope for 4.81 s? (b) How far does the skier travel in this time?arrow_forwardAn unidentified flying object (UFO) is observed to travel a total distance of 49000 m, starting and ending at rest, over a duration of 3.07 s. Assuming the UFO accelerated at a constant rate to the midpoint of its journey and then decelerated at a constant rate the rest of the way, what was the magnitude of its acceleration? Express your answer in g s , where 1 g = 9.81 m/s^2. 20,796 g s 10,398 g s 2,120 g s 1,060 g sarrow_forward
- What is the magnitude of the average acceleration of a skier who, starting from rest, reaches a speed of 11.4 m/s when going down a slope for 3.16 s? (b) How far does the skier travel in this timearrow_forwardA rocket blasts off and moves straight upward from the launch pad with constant acceleration. After 2.8 seconds the rocket is at a height of 91 meters. (A) What are the magnitude and direction of the rocket's acceleration? (B) What is it's speed at this time? Can you please solve the question using one or more of these equations: v = v0 +at vav = (1/2) times (v0 + v) x = x0 + (1/2) times (v0 + v) times t x = x0 + v0t + (1/2)at2 v2 = v02 + 2a(x - x0)arrow_forward(a) What is the magnitude of the average acceleration of a skier who, starting from rest, reaches a speed of 8.06 m/s when going down a slope for 1.61 s? (b) How far does the skier travel in this time?arrow_forward
- An automobile travels on a straight road for 34 km at 36 km/h. It then continues in the same direction for another 34 km at 72 km/h. (a) What is the average velocity of the car during this 68 km trip? (Assume that it moves in the positive × direction.) (b) What is the average speed?arrow_forwardA train, traveling at a constant speed of 22.0 m/s, comes to an incline with a constant slope. While going up the incline, the train slows down with a constant acceleration of magnitude 1.40 m/s2. (A) What is the speed of the train after 7.20 s on the incline? (B) How far has the train traveled up the incline after 7.20 s?arrow_forwardAssume you are driving a car at a constant speed of 76 km/h. Suddenly you see a deer standing on the highway and you must put on the brakes. Your reaction time (time elapsed between the moment you see the deer and your foot hitting the brakes) is 0.118 s. The brakes provide an acceleration with a magnitude of 4 m/s2, and a direction opposite the initial velocity. How do you find the total distance traveled?arrow_forward
- A cargo helicopter, descending steadily at a speed of 3.8 m/s, releases a small package. Let upward be the positive direction for this problem. (a) If the package is 94 m above the ground when it is dropped, how long does it take for the package to reach the ground? (a) What is the initial velocity of the package? How does it compare to that of the helicopter? What is its sign? What about the magnitude and sign of the acceleration? s(b) What is its velocity just before it lands? (Indicate the direction with the sign of your answer.)arrow_forwardA person walks 20.0 meters in a straight line. Then the person turns around and walks back 18.0 meters along the same line. The time for the walk is 9.00 seconds.(a) What is the average speed for this walk?(b) What is the average velocity for this walk?(c) What is the displacement?(d) What is the total distance?arrow_forwardThe velocity of a particle moving along the x-axis varies in time according to the expression v(t) = α - βt2 where α = 52.9m/s , β = 3.72m/s3, and t is in seconds. a) Find the acceleration in the time interval from t = 0 to 2.97s in units of m/s2 b) Determine the acceleration of the particle tf = 2.97s in m/s2arrow_forward
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