An athlete is training on a 100 m long linear track. His motion is described by the graph of his position vs. time, below. x (m) 100 80 60 40 20 direction VA magnitude v VA direction VC magnitude VD B 10 (a) For each segment of the graph, find the magnitude and direction of the athlete's velocity. magnitude VA 0 X D 20 30 40 50 60 t (s) Remember that velocity is the change in position per the change in time. If the graph plots position vs. time, what property of the plot in each segment is related to velocity? Think about the initial and final times and positions for each segment. m/s The magnitude is zero. X -1.33 x Remember that velocity is the change in position per the change in time. If the graph plots position vs. time, what property of the plot in each segment is related to velocity? Think about the initial and final times and positions for each segment. m/s negative x ✓X direction VB 4 X magnitude vc Remember that velocity is the change in position per the change in time. If the graph plots position vs. time, what property of the plot in each segment is related to velocity? Think about the initial and final times and positions for each segment. m/s positive x v x 1.67 positive x x Remember that velocity is the change in position per the change in time. If the graph plots position vs. time, what property of the plot in each segment is related to velocity? Think about the initial and final times and positions for each segment. m/s positive x direction VD (b) What are the magnitude and direction of the athlete's average velocity over the entire 60 s interval? m/s magnitude direction

An object’s position as a function of time is x(t) = 9 m + 1.5 m/s t– 3 m/s^2 t^2a. Calculate the object’s position, velocity, and acceleration at t = 6.2 s. At this point in time, is the object to the left or to the right of the origin? is it moving towards the left or towards the right? is the object speeding up or slowing down?b. What is the maximum positive displacement reached?

An athlete is training on a 100 m long linear track. His motion is described by the graph of his position vs. time, below. For each segment of the graph, find the magnitude and direction of the athlete's velocity. magnitude vA _______ m/s   direction vA(Pick from the following choices)- Positive x- Negative x- The magnitude is zero   magnitude vB _______ m/s   direction vB(Pick from the following choices)- Positive x- Negative x- The magnitude is zero   magnitude vC _______ m/s   direction vC(Pick from the following choices)- Positive x- Negative x- The magnitude is zero magnitude vD _______ m/s   direction vD(Pick from the following choices)- Positive x- Negative x- The magnitude is zero

An athlete is training on a 100 m long linear track. His motion is described by the graph of his position vs. time, be x (m) 100 80 60 40 20 A magnitude VB direction VB magnitude vc direction VC magnitude VD direction VD 10 ---Select--- ---Select--- 20 30 40 50 60 (a) For each segment of the graph, find the magnitude and direction of the athlete's velocity. magnitude VA m/s direction v ---Select--- B ---Select--- ---Select--- m/s с m/s D m/s t (s) (b) What are the magnitude and direction of the athlete's average velocity over the entire 60 s interval? magnitude m/s direction