An astronaut exploring a distant solar system lands on a planet with with a radius of 2,360 km and a gravitational acceleration of 7.46 m/s2. The astronaut launches a space probe straight up starting with an initial speed of 1.10 km/s. What is the height the space probe could reach? (consider G=6.67×10–11 m3kg–1s–2)

The International Space Station, which has a mass of 4.94×105 kg, orbits 258 miles above the Earth's surface, and completes one orbit every 94.3 minutes. What is the kinetic energy of the International Space Station in units of GJ (109 Joules)? (Note: don't forget to take into account the radius of the Earth!) Enter answer here GJ

Comets travel around the sun in elliptical orbits with large eccentricities. If a comet has speed 3.1x10^4 m/s when at a distance of 2.7x10^11 m from the center of the sun, what is its speed when at a distance of 4.7x10^10 m? Mass of the Sun is 1.99×10^30 kg. Gravitational constant is G=6.67×10^(−11) m^3 /(kg⋅s).   What is the formula?   (Answer: 75006.70209088 m/s)

A sun rays take about 8 minutes to reach the Earth surface travelling at constant speed v= 3,0 * 10^8 m/s. How far is earth from the sun?

A rocket moving around the earth at height "H", If the gravitational acceleration "gl" at height “H" is ½ of gravitational acceleration 'g' at earth surface. If Earth radius is"R", find "H" using R.

A projectile is shot straight up from the earth's surface at a speed of 1.00×104 km/hr .How high does it go?

An object is thrown upward with a speed of 16.3 m/s on the surface of planet X where the acceleration due to gravity is 1.8 m/s. What is the maximum height reached by the object? Answer: Check

An extrasolar planet has mass 1.27E+25 kg and radius 67400000_m. What is the escape speed for this planet? 11440_m/s 12230_m/s 5014_m/s А. D. 16190_m/s В. Е. 1973_m/s С. F. 9206 m/s

When a falling meteor is at a distance 3.58times the radius of the Earth above theEarth’s surface, what is its free-fall acceleration? The acceleration of gravity is9.8 m/s squared. , the universal gravitational constant is 6.67259×10−11 N · m2/kg2 and the Earth’sradius is 6.37 × 106 m. Answer in units of m/s 2.

2/113 A space shuttle which moves in a circular orbit around the earth at a height h 150 mi above its surface must have a speed of 17,369 mi/hr. Calculate the gravitational accelerationg for this altitude. The mean radius of the earth is 3959 mi. (Check your an- swer by computing g from the gravitational law g = R go where go = 32.22 ft/sec2 from Table D/2 R+h in Appendix D.)