An ASP operating at equilibrium has an organic loading rate of 2 kg/m³/d and has MLSS of 3000 ratio is mg/1 in the aeration tank. The d-1 (round off to two decimal places). F Food M Biomass,

A waste treated using an activated sludge process has an aeration basin with a volume of 10^6 Land a solid retention time of 4 days. What would the mass flow of wasted solids be in this system (kg/day) if the biomass in the aeration basin is 3000 mg/L and that in the wasted sludge is 12,500 mg/L?

2. The raw water to be coagulated has a pH of 7.5, determine how much alkalinity the water must have for the addition of 150 mg/L alum without affecting the pH.

A waste of 600 m³/hr flow rate with an ultimate BOD20 = 140 mg/l is to be treated in an activated sludge process to yield an effluent of 20mg/1 BOD5 and 25mg/1 suspended solids. For the reactor the detention time = 6 hrs, sludge age = 10days, under flow SS concentration = 15000mg/l, decay rate = 0.055 day, yield coefficient = 0.65, BOD of the effluent SS =60% of the suspended solid concentration and the solids are 80% volatile. ( k₁, 20 = 0.24 /day) Find: -1- MLSS (mg/l) 2- Recirculation ratio

The wastewater from a synthetic textile manufacturing plant is discharged to a municipal treatment plant for processing with domestic wastewater. The characteristics of the synthetic textile wastewater are 1500 mg/L BOD, 2000 mg/L SS, 30 mg/L nitrogen, and no phosphorus. The characteristics of the domestic wastewater are 200 mg/L BOD, 240 mg/L SS, 35 mg/L nitrogen, and 7 mg/L phosphorus. Find the BOD, SS of the mixture. The ratio of flow rate is domestic/textile = 4/1

Q2) A waste of 600 m*hr flow rate with an ultimate BODZ° = 140 mg/l is to be treated in an activated sludge process to yield an effluent of 20mg/l BOD5 and 25mg/l suspended solids. For the reactor the detention time = 6 hrs , sludge age = 10days , under flow SS concentration = 15000mg/1 , decay rate = 0.055 day , yield coefficient = 0.65 , BOD of the effluent SS =60% of the suspended solid concentration and the solids are 80% volatile.( ky, 20 = 0.24 /day) Find: - 1- MLSS (mg/l) 2- Recirculation ratio

These are waste from industrial areas that undergoes several processes. Residential Wastewater Industrial Wastewater Storm Wastewater D Agricultural Wastewater

An activated sludge treatment process uses a rectangular tank that can be modeled as two completely mixed reactors in series. The volume of the tank is 300 cubic meters (for modeling purposes 150 cubic meters each) and the flow rate into the system is 900 m3/day. The influent BOD concentration is 180 mg/L and the first order reaction rate coefficient is 0.5 hr-1.   What is the effluent concentration of BOD? If the Biomass Yield, Y is equal to 0.6 mg SS/mg of BOD metabolized, what is the rate of SS (biomass) production in the aeration tanks (mg/L-day)? If the post-secondary clarifier effluent SS concentration is 10 mg/L, the sludge recycling rate is 33%, and the waste sludge flow rate is 5 m3/day, what is the SS concentration in the waste sludge (hint: assume the system is at steady state and complete a mass balance)?  What is the sludge age?

An activated sludge system using CSTR with sludge recycle has an influent flow rate (Q°) of 2.5 MGD that contains BOD of 200 mg/L. The volume of the aeration tank (CSTR) is 0.6 million gallons. The MLVSS (assume this is X,) in the aeration tank is 2000 mg VSS/L and the decay rate (b) is 0.1/day. The effluent from the secondary clarifier meets NPDES standards for suspended solids and BOD. The concentration of the settled sludge exiting the bottom of the secondary clarifier is 15,000 mg VSS/L. The sludge waste flow rate (Q") is 1 % of the influent flow rate, and the effluent flow rate (Qª) is ~99% of the influent flow rate. а) What is the hydraulic retention time, 0 (d)? b) What is the solids retention time, 0x (d)? Activated sludge with recycle с) What is the F/Ma ratio?

The dilution water which is to be used for the BOD analysis on an industrial waste was seeded with nitrified sewage effluent so that the initial bacterial density in the mixture is 40 cells per ml. The time required to produce a bacterial density of 108 cells per ml, if the specific growth rate of bacteria is 0.04 min-1 is