An article reported that, in a study of a particular wafer inspection process, 356 dies were examinedstable process, calculate a 95% (two-sided) confidence interval for the proportion of all dies that passX,XYou may need to use the appropriate table in the Appendix of Tables to answer this question.byan inspectionthe probe.probe(Roundand 196 of thesepassedto three decimalyour answersthe probe. Assuming aplaces.)

A sample of 356 dies were examined by an inspection probe and 196 of these passed the probe.

Answered: An article reported that, in a study of…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Suppose that in a sample of 4876customers at a food store, 2654food shop more than once a week. Find a 90% confidence interval for the population proportion of customers who shop more than once a week. Interpret your answer. b) A claim is made that 52% of all customers at a food store shop more than once a week. Using the results from part (a) of this problem, would this claim be valid or invalid?
In a random sample of 1500 BA majors who are graduating from the University of Cape Town this autumn(2020), we observe that 1380 have already found a job.Question 3Calculate the 95 % Confidence interval for the proportion in Question 6 above. Round off to six decimals and show all workings.
The trade magazine QR routinely checks the drive-through service times of fast-food restaurants. A 99% confidence interval that results from examining 719 customers in Taco Bell's drive-through has a lower bound of 159. 1 seconds and an upper bound of 162.1 seconds. Complete parts (a) through (c).
From a random sample of 1000 houses in a city, it is found that 628 houses use natural gas heating. - Create a 98% confidence interval for the proportion of houses in the city that use natural gas heating - How large a sample is needed if we want to believe 98% that the proportion of the sample found lies within a distance of no more than 0.05 from the true proportion?
To find the proportion of San Diegans subscribed to Disney+ in 2019, a researcher randomly selected 200 people from San Diego and found that 101 were subscribed. a) Check that the assumptions are met for a confidence interval for proportions.
In another pre-election poll, a pollster finds that 442 out of 650 people polled favor Smith. Construct the 95% confidence interval for the proportion (to nearest 0.001) of people in the whole population who favor Smith.
In a certain village in Turkey, a sample of 250 cl of drinking water is examined and it is foundout that 160 of the sample is contaminated with sewage. Construct a 97% confidence interval for the corresponding true proportion.
In a preelection poll, a pollster finds that 442 out of 650 people polled favor Smith. Construct the 95% confidence interval for the proportion (nearest to 0.0001) of people in the whole population who favor Smith.
In a survey of health workers, 25 percent stated that they expect to be promoted after 3 years of service. If this percentage holds for the entire population, in a sample of 9 health workers drawn from this population. a) Between six and nine, inclusive b)If we draw a sample of 45 health workers from this population where, determine a 95% and 99% confidence interval for the true proportion of health workers who expect a promotion after 3 years of service
A yogurt company claims that it prints a free yogurt coupon under a randomly selected 20% of its lids. A loyal customer purchases 85 yogurt cups, and records whether each was a winner. After consuming all 85 cups, he is disappointed to see that only 12 (14.1%) of his yogurt cups contained coupon codes. He performs a 99% confidence interval for the proportion of yogurt cups containing coupon codes, obtaining (0.044, 0.238). What conclusion can the customer draw about the yogurt company’s claim? The company’s claim may be justified because 0.2 is in the confidence interval. The company’s claim is definitely justified because 0.2 is in the confidence interval. The company’s claim is not justified because the upper endpoint of the confidence interval is 0.238. The company’s claim is not justified because 12 out of 85 (0.141) is far less than 0.2.
A department store finds that in a random sample of 200 customers, 60% of the sampled customers had browsed its website prior to visiting the store. Based on this data, a 90% confidence interval for the population proportion of customers that browse the store’s website prior to visiting the store will be between _________________. 0.6588 and 0.6312 0.4528 and 0.5250 0.5960 and 6040 0.5978 and 0.6022 0.5430 and 0.6570
In a survey of 500 potential jurors, one study found that 350 were regular watchers of at least one crime-scene forensics television series. (a) Assuming that it is reasonable to regard this sample of 500 potential jurors as representative of potential jurors in the United States, use the given information to construct a 95% confidence interval for the true proportion of potential jurors who regularly watch at least one crime-scene investigation series. (Give the answer to three decimal places.)( , )

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