An area of a circular sector is 50m? with radius of 5 m. Find the length of the same sector.

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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**Problem Statement:**

An area of a circular sector is \(50 \, \text{m}^2\) with a radius of \(5 \, \text{m}\). Find the length of the same sector.

**Solution Explanation:**

To find the length of the sector, first, we need to determine the angle of the sector in radians. The area \(A\) of a circular sector is given by the formula:

\[ A = \frac{1}{2} \times r^2 \times \theta \]

Where:
- \( A \) is the area of the sector,
- \( r \) is the radius,
- \( \theta \) is the angle in radians.

Given:
\[ A = 50 \, \text{m}^2 \]
\[ r = 5 \, \text{m} \]

Substitute the known values into the formula and solve for \(\theta\):

\[ 50 = \frac{1}{2} \times 5^2 \times \theta \]

\[ 50 = \frac{1}{2} \times 25 \times \theta \]

\[ 50 = 12.5 \times \theta \]

\[ \theta = \frac{50}{12.5} \]

\[ \theta = 4 \, \text{radians} \]

Now, to find the arc length \(L\), use the formula:

\[ L = r \times \theta \]

Substitute the known values:

\[ L = 5 \times 4 \]

\[ L = 20 \, \text{m} \]

Therefore, the length of the sector is \(20 \, \text{m}\).
Transcribed Image Text:**Problem Statement:** An area of a circular sector is \(50 \, \text{m}^2\) with a radius of \(5 \, \text{m}\). Find the length of the same sector. **Solution Explanation:** To find the length of the sector, first, we need to determine the angle of the sector in radians. The area \(A\) of a circular sector is given by the formula: \[ A = \frac{1}{2} \times r^2 \times \theta \] Where: - \( A \) is the area of the sector, - \( r \) is the radius, - \( \theta \) is the angle in radians. Given: \[ A = 50 \, \text{m}^2 \] \[ r = 5 \, \text{m} \] Substitute the known values into the formula and solve for \(\theta\): \[ 50 = \frac{1}{2} \times 5^2 \times \theta \] \[ 50 = \frac{1}{2} \times 25 \times \theta \] \[ 50 = 12.5 \times \theta \] \[ \theta = \frac{50}{12.5} \] \[ \theta = 4 \, \text{radians} \] Now, to find the arc length \(L\), use the formula: \[ L = r \times \theta \] Substitute the known values: \[ L = 5 \times 4 \] \[ L = 20 \, \text{m} \] Therefore, the length of the sector is \(20 \, \text{m}\).
Expert Solution
Step 1

The given data is:

The area of the circular sector is A=50 m2

Radius r=5 m

To find the length of the same sector.

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