Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Question

need help with finding molarity thanks! 

**Problem Statement:** An aqueous potassium iodate (KIO₃) solution is made by dissolving 548 grams of KIO₃ in sufficient water so that the final volume of the solution is 3.90 L. Calculate the molarity of the KIO₃ solution. **Equation to Solve:** \[ \text{[KIO}_3\text{]} = \] **Solution Approach:** To determine the molarity of the KIO₃ solution, use the formula: \[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \] **Steps:** 1. **Calculate the moles of KIO₃:** - Determine the molar mass of KIO₃ using atomic masses (K: 39.10 g/mol, I: 126.90 g/mol, O: 16.00 g/mol). - Molar mass of KIO₃ = 39.10 + 126.90 + 3(16.00) = 214.00 g/mol. - Moles of KIO₃ = \(\frac{548 \text{ g}}{214.00 \text{ g/mol}}\). 2. **Calculate the molarity:** - Use the calculated moles of KIO₃ and the given volume of the solution (3.90 L) to find molarity. \[ \text{[KIO}_3\text{]} = \text{moles of KIO}_3 \div 3.90 \text{ L} \]
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Transcribed Image Text:**Problem Statement:** An aqueous potassium iodate (KIO₃) solution is made by dissolving 548 grams of KIO₃ in sufficient water so that the final volume of the solution is 3.90 L. Calculate the molarity of the KIO₃ solution. **Equation to Solve:** \[ \text{[KIO}_3\text{]} = \] **Solution Approach:** To determine the molarity of the KIO₃ solution, use the formula: \[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \] **Steps:** 1. **Calculate the moles of KIO₃:** - Determine the molar mass of KIO₃ using atomic masses (K: 39.10 g/mol, I: 126.90 g/mol, O: 16.00 g/mol). - Molar mass of KIO₃ = 39.10 + 126.90 + 3(16.00) = 214.00 g/mol. - Moles of KIO₃ = \(\frac{548 \text{ g}}{214.00 \text{ g/mol}}\). 2. **Calculate the molarity:** - Use the calculated moles of KIO₃ and the given volume of the solution (3.90 L) to find molarity. \[ \text{[KIO}_3\text{]} = \text{moles of KIO}_3 \div 3.90 \text{ L} \]
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