An ant walks on a piece of graph paper straight along the x axis a distance of 10.0 cm in 2.20s. It then turns left 30.0 degrees and walks in a straight line another 10.0 cm in 1.90s. Finally, it turns another 70.0 degrees to the left and walks another 10.0 cm in 1.40s. Determine the y component of the ant's average velocity.

Q: Two experts are 20.00mm apart at closest approach. What is the magnitude of the maximum electric…

A:

Q: A charged particle moves with a uniform velocity 4.3 ŷ (m/s) in a region where E = 192 (V/m) and B =…

A: Given: Charged particle moving velocity, v→=4.3y^ ms Electric field, E→=19z^ Vm Magnetic field…

Q: Multiple-Concept Example 3 provides some pertinent background for this problem. Suppose a single…

A:

Q: A proton is released from rest in a uniform horizontal electric field. It travels 3.25 m from 5μs.…

A:

Q: A vector field is defined by v = (yz, xz, xy). Show that curl v = 0.

A: v=(yz,xz,xy)

Q: In concntric spherical shells w/c is equipotential surface, what is the work done in moving a…

A:

Q: Compute for the potential difference, in volts, in moving a charge radially away from the center…

A: Gauss law of electrostatics: According to this law, the amount of electric flux passing through a…

Q: E ere, a positively charged particle q is traveling in the +y direction with elocity i through a…

A:

Q: If a proton and electron are released when they are 2.0  m apart, find the initial acceleration of…

A: Fe=14π∈0q1q2r2q1=e; q2=-e ;e=1.6×10-19 ; r=2 ;14π∈0=9×109Fe=-9×109×e24=-5.76×10-29Fe=5.76×10-29(sign…

Q: Alex the Astronaut weighs 70 kg. He is space walking outside the space shuttle and pushes a 350-kg…

A:

Q: A dsik of radius R-1m and charge Q-ImC is homogeneously charged. Find the electric potential at che…

A: Given: Q=1mC = 10-3 C R=1m

Q: An electron with initial velocity vo enters a region of with a uniform field E vertically directed.…

A: v0=107 cm/sE=1000 V/mϑ=45°m=10-31 kge=1.6×10-19 C We can solve this problem using conservation of…

Q: When an electron is accelerated from rest to potential V, the final velocity of electron is (a) (c)…

A: We must determine the electron's ultimate velocity.The electron is propelled from rest to potential…

Q: If a proton and an electron are released when they are 4.00 x 10-10m apart, find the initial…

A:

Q: What is the electrical potential at the center (point O) of a non- uniformly charged semicircular…

A: Potential at the centre o is kqRthen, q=∫λ dlIn polar coordinate∫dl=∫r dθ

Q: 1) A proton (p) and electron (e-) are released when they are 4 Å (4 Angstroms). Find the initial…

A: As per the guidelines first question answered. Kindly post remaining question as new question

Q: Ex obtain the weater magnatic folartal A in the regrin Surounding arent? infinitely long, straight…

A: The equation for magnetic vector potential for a filament wire carrying steady current I is give as,…

Q: An electron (m = 9.11 x 10-31 kg) in empty space experiences an upward electric force equal to 25…

A: The given data are listed below with suitable variables. Here, m denotes the electron’s mass, F…

Q: The friends now try a homework problem. Consider an electron, of charge magnitude e = 1.602 × 10-1⁹…

A:

Q: An electron is fired at a speed vj = 3.4 x 106 m/s and at an angle 0; = 30.5° between two parallel…

A:

Q: For a spherical surface with radius 0.33 m and is charged by 26 nC, the electric Potential V at r =…

A: Given data: Radius of spherical surface is, R=0.33 m. Magnitude of charge is, q=26 nC=26×10-9 C.

Q: 2. (a) Two protons are separated by a distance, 2a, where a = 5.0 x 10-10 m. As in the figure, on…

A: Given: The separation between protons is 2a. a=5×10-10 m

Q: A proton accelerates from rest in a uniform electric fe d of 626 N/C. AL Seme fater time, its speed…

A:

Q: At this point if we place a proton at the origin then the proton will feel an acceleration. To keep…

A: Given: q1=-25 nC=-25×10-9 Cq2=40 nC=40×10-9 Cb=33 nm=33×10-9 m∴b2=16.5×10-9 me=-1.6×10-19 C A proton…

Q: Prove that the direction of electric field strength is perpendicular to surfaces of equal electric…

A:

Q: وابع الرق - Astlerical charge of (Svz 6cfm?) and ra dins #s cen tr is at (le23) (E)at Point (3,-2w…

A: Here the spherical charge of density ρv=6 C/m3 and radius 4 and its center at (1,2,3). The center is…

Q: A particle of mass m carrying a charge - starts moving around a fixed charge +92 along a circular…

A:

Q: A particle of mass m carrying a charge -1 starts moving around a fixed charge +92 along a circular…

A:

Q: For a spherical surface with radius 0.18 m and is charged by 23 nC, the electric Potential V at r =…

A: Given: The radius of the spherical surface is 0.18 m. The charge on the surface is 23 nC. The…

Q: An electron is projected with horizontal velocity of magnitude vo into a constant downward electric…

A:

Q: centripetal acceleration

A: Coulomb force provides centripetal force

Q: In the figure below, determine the point (other than infinity) at which the electric field is zero.…

A: Given: q1 = -1.65 μCq2 = 6.90 μC   To Find: The distance of the point at which the electric field is…

Q: A long coaxial cable carries a positive uniform volume charge density, ρ, on the inner cylinder…

A: Given:inner cylinder radius, aouter cylinder radius, binner cylinder volume charge, +ρ  C/m3outer…

Q: For a uniformly charged conductor, O E = 0 inside the conductor O V = 0 inside the conductor O V = 0…

A: Electric field must be zero inside the conductor That isIf electric field not zero inside the…

Q: Two fields distribution are given below; (a) V = P cos 0 4ze,R² and (b) A=â„3cos0+2â‚R² sin 0- â̟…

A: The gradient, divergence & curl in vector form can be written using the standard method as…

Q: or a spherical surface with radius 0.36 m and is charged by 26 nC, the electric Potential V at r =…

A: Given- Radius of surface (r) = 0.17 m Charge on surface (Q) = 26 nC = 26 x 10-9 C

Q: Find magnitude of acceleration for a Proton in electric field 576 N/C.

A:

Q: 7. a) Find the divergence of the vector field G(x, y, z)= exi+ln(xy) j+exyz k at (0.2, -31 b) Find…

A: