An analytical chemist is titrating 169.0 mL of a 0.8600M solution of methylamine (CH3NH₂) with a 0.2200M solution of HIO3. The pK, of methylamine is 3.36. Calculate the pH of the base solution after the chemist has added 527.8 mL of the HIO3 solution to it. Nate for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HIO3 solution added. Round your answer to 2 decimal places.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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### pH Calculation of a Titration of Methylamine with HIO3

An analytical chemist is performing a titration using:

- **169.0 mL** of a **0.8600 M** solution of methylamine (CH3NH2)
- A **0.2200 M** solution of HIO3. 

The provided base dissociation constant (\( pK_b \)) of methylamine is **3.36**.

#### Problem Statement:
Calculate the pH of the base solution after the chemist has added **527.8 mL** of the HIO3 solution to it.

**Note for advanced students:** 
You may assume that the final volume equals the initial volume of the solution plus the volume of the HIO3 solution added.

**Instructions:**
- Round your answer to two decimal places.

### Input Section:

The input fields include a space for the calculated pH value:
- `pH = __`

Below the input field, there are three buttons:
1. A green check (✔︎) to submit the answer.
2. A circular arrow (⟳) for resetting the input.
3. A question mark (?) for providing help or guidance.

### Explanation:

This educational task guides the user through a titration problem involving the calculation of pH after mixing two solutions. The critical aspects are:

1. **Initial Concentration and Volume of Methylamine:**
   - Volume: 169.0 mL
   - Concentration: 0.8600 M
2. **Concentration and Volume of HIO3 Added:**
   - Volume: 527.8 mL
   - Concentration: 0.2200 M
3. **pK_b of Methylamine:**
   - Value: 3.36

### Steps for Calculation:

1. Determine the moles of CH3NH2 and HIO3 initially present.
2. Use the volumes added to find the new concentrations of CH3NH2 and the resulting species in the final solution.
3. Compute the resulting pH after the titration using equilibrium expressions and the given \( pK_b \).

By following these steps, students will practice key concepts in acid-base chemistry, equilibrium, and pH calculations during titrations.
Transcribed Image Text:### pH Calculation of a Titration of Methylamine with HIO3 An analytical chemist is performing a titration using: - **169.0 mL** of a **0.8600 M** solution of methylamine (CH3NH2) - A **0.2200 M** solution of HIO3. The provided base dissociation constant (\( pK_b \)) of methylamine is **3.36**. #### Problem Statement: Calculate the pH of the base solution after the chemist has added **527.8 mL** of the HIO3 solution to it. **Note for advanced students:** You may assume that the final volume equals the initial volume of the solution plus the volume of the HIO3 solution added. **Instructions:** - Round your answer to two decimal places. ### Input Section: The input fields include a space for the calculated pH value: - `pH = __` Below the input field, there are three buttons: 1. A green check (✔︎) to submit the answer. 2. A circular arrow (⟳) for resetting the input. 3. A question mark (?) for providing help or guidance. ### Explanation: This educational task guides the user through a titration problem involving the calculation of pH after mixing two solutions. The critical aspects are: 1. **Initial Concentration and Volume of Methylamine:** - Volume: 169.0 mL - Concentration: 0.8600 M 2. **Concentration and Volume of HIO3 Added:** - Volume: 527.8 mL - Concentration: 0.2200 M 3. **pK_b of Methylamine:** - Value: 3.36 ### Steps for Calculation: 1. Determine the moles of CH3NH2 and HIO3 initially present. 2. Use the volumes added to find the new concentrations of CH3NH2 and the resulting species in the final solution. 3. Compute the resulting pH after the titration using equilibrium expressions and the given \( pK_b \). By following these steps, students will practice key concepts in acid-base chemistry, equilibrium, and pH calculations during titrations.
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