Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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An amplifier operating from a ±15 V DC supply provides an output voltage of 20 V peak-to-peak and an output current of 23 mA peak to a resistive load when a signal of 2 V peak is connected to its input. The current drawn by the input port of the amplifier is 2 mA rms. A current of 15 mA DC is provided by each DC power supply. For this amplifier, calculate:
the voltage gain in dB
the current gain in dB
the power gain in dB
the efficiency (as a percentage)
the input resistance in Ohms
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- 1. Assume that the gm of Q, is 1500 umhos for the amplifier in the following figure. a. Compute. b. If gm = 1500 umho, what is the voltage gain? What is You? d. What is the purpose of C₂? What happens if it is open? C. V 200 mV pp 10 kHz HI 0.1 μF WI Ra 1.0 MO +VDD +15 V RD 6.2 k0 C3 -EE -15 V 9₂₁ 2N5458 l₂ 2N3904 RE 15 ΚΩ 0.1 μF 22 μFarrow_forwardDesign an transistor amplifier with a total voltage gain of 40. The signal source has a 10 kohm impedance. The load is 5 kohms. Please show all work.arrow_forwardVoD +12 V For the circuit of the adjacent figure a) Given that Ip = 2.83 mA, VGS(om=-7 V and Ipss = 8 mA , find VDs and VGs.. b) If a 50 mV rms input signal is applied to the amplifier, what is the peak-to-peak output voltage? gm = 5000 µS. c) Calculate the output resistance. %3D Ro 10AF 0.1 uF R 10 L. Ra 10 MA 10kn ID= 2.83 mA, Vas (Oef)=-7V. %3Darrow_forward
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