Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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- Consider the integrating amplifier circuit in Figure 2. Using nodal analysis, derive an expression for vout for the integrating amplifier. In the circuit in Figure 2, exchange the positions of the 0.1uF capacitor and the 5k resistor. a. Use nodal analysis to generate an expression for vout. b. Using this expression, explain what function this circuit performs on an input signal.arrow_forwardFigure 2 shows a typical BJT amplifier, with its parasitic capacitances displayed. The current gain of the transistor is B=150 and the voltage gain of the amplifier is Am =-125. The small signal resistances of the transistor are re =16 ohm and r0 = infinity, respectively. The values of resistors and capacitors in the figure are: R1 =80 kohm, R2 =20 Kohm, Rc = 2 Kohm, RE = 2 Kohm, Rs =50 W, RI=5 kohm, Cs=2 uF, Cc=2 uF, Ce =10 uF, Cbc =4 pF, Cbe = 10 pF, Cce =1 pF, Cwi = 4 pF, CWO = 9 pF, and Vcc = 20 V. a) Sketch a simplified circuit diagram of Figure 2 for high frequency analysis. b) Using the concept of "Miller effect capacitance", calculate the input and Output Miller effect capacitances of Figure 2, respectively. C) Determine the upper cut-off frequency of Figure 2 that is imposed by its input network only. d) Explain briefly the possible ways to increase the upper cut-off frequencv of this amplifier.arrow_forwardVoD +12 V For the circuit of the adjacent figure a) Given that Ip = 2.83 mA, VGS(om=-7 V and Ipss = 8 mA , find VDs and VGs.. b) If a 50 mV rms input signal is applied to the amplifier, what is the peak-to-peak output voltage? gm = 5000 µS. c) Calculate the output resistance. %3D Ro 10AF 0.1 uF R 10 L. Ra 10 MA 10kn ID= 2.83 mA, Vas (Oef)=-7V. %3Darrow_forward
- Please solve with steps, using to study. Will upvote!arrow_forwardIn an emitter-biased transistor circuit, we have collector source voltage V CC = 15 V, collector resistance RC = 3.5 kOhm, emitter voltage V_E = 4.3 V and emitter current LE = 2.1 mA. If the current gain is 150, what is the difference in emitter-collector voltage V_CE when we calculate it including the gain factor vs when it is calculated by assuming collector current LC = LE? Select one: O a. 3.35 V O b. 3.40 V OC 0.05 V O dovarrow_forwardplease solvearrow_forward
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