An aluminum tube of outer diameter R, = 50 mm is heated such that it is mounted over a steel shaft of radius, R1 = 20 mm as shown in the figure. The length I of the member is 3 m. MT R Ri If a G = 77.2 GPa, G2 = 27 GPa, and torque of MT = 36 kN.m is applied to induce twisting in the member, Determine the maximum shear stress in shaft 1 777

An aluminum tube of outer diameter R, = 50 mm is heated such that it is mounted over a steel shaft of radius, R1 = 20 mm as shown in the figure. The length I of the member is 3 m. MT R Ri If a G = 77.2 GPa, G2 = 27 GPa, and torque of MT = 36 kN.m is applied to induce twisting in the member, Determine the maximum shear stress in shaft 1 777

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

A 28mm diameter steel shaft AB is built into a rigid wall at A and supported by a smooth bearing at B. The lever BC is welded to the end of the shaft. Load P 360 newton is applied as shown in the figure below. Determine the maximum shear stress and the angle of twist if the distance from A to B is 3 meters and the distance from B to C is .3 meters
T.L Tr4 %3D J = " (r* – rf) (Tubular shaft) Tr (Solid shaft) G.J 3. The shaft in the figure below consists of 75 mm diameter bronze segment that is rigidly joint to 50 diameter steel segment. The ends of the shaft are attached to rigid supports (fixed supports). Calculate the absolute maximum shear stress developed in each segment when the torque T= 5.1 kN-m is applied (a = 2 m and b = 1.5 m). Use G = 35 GPa for bronze, and G = 75 GPa for steel. (21 pts) 75 mm 50 mm Bronze Steel
The circular cross-section, L=0.5m long console BC shaft in the figure is forced to twist with P1=2 kN, P2=8 kN due to the forces on the belts connected to the pulley C. The radius of the pulley is R=0.4m and its weight is W=3 kN. Calculate shaft diameter D based on the assumption of maximum shear stress (TRESCA). Yield strength of the shaft = 240MPa and safety factor is S=2 1 kasnak D 2R P2 |B kayış y
A shaft ABCD is supported by a clamp at point A and is subjected to point torques at B, C and D, as shown in the figure. The shaft has variable cross-section and is solid in segments AB and CD and hollow in segment BC. The lengths and diameters of each segment are shown in the figure. Assume that the deformation is linear elastic and take the shear modulus of elasticity G = 12.1 × 10° psi. a) Using method of sections, plot the torsion moment diagram. b) Find the angle of twist for the free end (point D) with respect to the fixed support at A, QAD and the angle of twist for point C with respect to the fixed support at A, QCA. Find both angles in degrees. d₁ = 4 in d20 3.5 in, d2=2.5 in d3 = 3.0 in 25 kip-in 20 kip-in 10 kip-in A 20 in B с D ++ 25 in 30 in
H K T A solid shaft is subjected to forces and a torque as shown in figure. The diameter of the shaft is 35 mm, T=75 N.m., V=3 kN, P=4,7 kN and L=117 mm. Determine the shear stress (T) at point H (MPa). Note: If the stress has negative direction, use sign. Yanıt:
An aluminum tube of outer diameter R2 = 50 mm is heated such that it is mounted over a steel shaft of radius, R = 20 mm as shown in the figure The length I of the member is 3 m. MT R Ri If a G, = 77.2 GPa, G2 = 27 GPa, and torque of MT = 36 kN.m is applied to induce twisting in the member, Determine the maximum shear stress in shaft 1. 777
Mechanics of Deformable Bodies
A torque of Tx=200Nm and a torque of Mz=260Nm are applied to the stepped shaft in the figure. Calculate the maximum stresses that will occur in the bar section, taking into account the stress concentration.
Figure 1 shows a composite shaft ABCD acted upon horizontal forces. The moduli of elasticity and the cross-section areas of the segments of the shaft are also provided. Eal 70 GPa E = 126 GPa E = 200 GPa AAR=58 mm² ABC 77 mm2 Acp = 39 mm² Сopper 20KN 8 kN Aluminum Steel 7 kN B 20KN A 8 kN 450 mm -300 mm -- 400 mm Figure 1: Axially loaded composite shaft 2.1. Construct the diagram of internal normal forces for each cross-section of the (6) shaft (3) 2.2. Calculate the displacement of the point C with respect to the fixed-point A 2.3. If the shaft must have one uniform diameter determine the required minimum diameter of the shaft if the normal yield stress in the composite shaft must not (11) exceed 450 MPa with a factor of safety equal to 1.8.
A round shaft of diamater D = 65 mm with a groove cut into it where the diameter decreases to d = 50 mm. The radius of the fillet at the groove is r = %3D 2.5 mm. If the internal torsional moment at a critical cross-section in the groove is 400 N.m, calculate the maximum torsional shear stress at the groove. Round-up your answer to the nearest MPa. Max torsional shear stress MPa