
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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An alpha particle (a helium nucleus) is traveling along the positive x-axis at 1100 m/s when it enters a cylindrical tube of radius 0.600 cm centered on the x-axis. Inside the tube is a uniform electric field of 4.00 10-4 N/C pointing in the negative y-direction. How far does the particle travel before hitting the tube wall? Neglect any gravitational forces.
Note: m? = 6.64 10-27 kg; q? = 2e.
m
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- A constant electric field of 20.0 N/C points along the positive x-direction. An electron, initially at rest, moves a distance of 0.500 m in this space. How fast is the electron moving after its 0.500 m journey?arrow_forward21.84 . CALC A semicircle of radius a is in the first and second y. quadrants, with the center of cur- vature at the origin. Positive charge +Q is distributed uniformly around the left half of the semicircle, and negative charge -Q is distributed uniformly around the right half of the semicircle (Fig. P21.84). What are the magnitude and direction of the net electric field at the origin produced by this distribution of charge? +Q x-arrow_forwardAn alpha particle (a helium nucleus) is traveling along the positive x-axis at 1075 m/s when it enters a cylindrical tube of radius 0.800 cm centered on the x-axis. Inside the tube is a uniform electric field of 3.00 10-4 N/C pointing in the negative y-direction. How far does the particle travel before hitting the tube wall? Neglect any gravitational forces. Note: m? = 6.64 10-27 kg; q? = 2e. marrow_forward
- A small drop of water is suspended motionless in air by a uniform electric field that is directed upward and has a magnitude of 7420 N/C. The mass of the water drop is 4.78 × 10-9 kg. How many excess electrons or protons reside on the droparrow_forwardPlease Asaparrow_forwardProblem 12: A simple and common technique for accelerating electrons is shown in the figure, which depicts a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to pass through. E = 2.4 × 104 N/C Calculate the horizontal component of the electron's acceleration if the field strength is 2.4 × 104 N/C. Express your answer in meters per second squared, and assume the electric field is pointing in the negative x-direction as shown in the figure.arrow_forward
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